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lana66690 [7]
3 years ago
11

In a photograph, a house is 4 inches wide and 6 inches tall. The photograph is enlarged while keeping proportional dimensions, a

nd the width of the house in the enlarged photograph is 9 inches. What is the height of the house in the enlarged photograph?
A)2.7 inches

B)6.0 inches

C)11.0 inches

D)13.5 inches
Mathematics
2 answers:
AlekseyPX3 years ago
6 0

Since you keep proportional dimensions, the proportion between the old and new dimensions must be the same. So, if we call the new height h, the preservation of the width/height ratio is written as


4 \div 6 = 9 \div h


Solving the proportion for h yields


h = \frac{6\cdot 9}{4} =\frac{3\cdot 9}{2} = \frac{27}{2} = 13.5

antiseptic1488 [7]3 years ago
3 0

Answer:

13.5

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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You have a 45-gallon jug and a 124-gallon jug. neither of the jugs has any markings (although you do know their capacities). des
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3 years ago
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ziro4ka [17]
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So increasing order with original numbers:
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7 0
3 years ago
14 times a number decreased By eight is 22 Increase by 20 times The same number
kotegsom [21]

Answer:

14x - 8 = 22 + 20x

x = -5

Step-by-step explanation:

Let "the number" be represented by x

Take each part of the statement and translate into algebraic form

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"decreased By eight" -8

"is" =

"22 Increased by" 22 +

"20 times The same number" 20x

Put the equation together. Solve for x by isolating.

(

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3 years ago
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Mkey [24]

The answer is 90°

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So,

180-(45+45)

= 180-90

= 90°


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4 years ago
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