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Vika [28.1K]
3 years ago
13

A solution is prepared by dissolving 0.23 mol of hydrazoic acid and 0.27 mol of sodium azide in water sufficient to yield 1.00 L

of solution.The addition of 0.05 mol of NaOH to this buffer solution causes the pH to increase slightly. The pH does not increase drastically because the NaOH reacts with the ________ present in the buffer solution. The Ka of hydrazoic acid is 1.9 ⋅ 10-5.
Chemistry
1 answer:
GarryVolchara [31]3 years ago
7 0

Answer:

The pH does not increase drastically because the NaOH reacts with the _HYDRAZOIC ACID__ present in the buffer solution.

Explanation:

NaOH reacts with the hydrazoic acid in the buffer

HN3 + OH? --> H2O + N3-

If you put acid in, it will react with N3-. Here is the equation below:

N3- + H+ --> HN3

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Which of the following is the valence elec- tronic structure for a halogen? 1. n s1 2. n s2 3. n s2 n d10 4. n s2 n p5 5. n s2 n
Arturiano [62]

Answer: option 4. ns² np⁵

Explanation:

The <em>valence electronic structure</em> of the compounds is the distribution of the valence electrons, i.e. the outermost electrons of the atoms.

The distribution of the electrons in the atomic orbitals is named electron configuration.

Each element has a proper electron configuration which is determined according to a series of rules: lowest orbital energy, Pauli's exclusion principle and Hund's rule.

The valence electronic structure of the atoms is related with the period (column of the periodic table) to which the element belongs.

Each period has a characteristic <em>valence structure</em> (number and location of the outermost electrons). It is this structure what conferes the elements of a same period (column in the periodic table) their similar chemical properties.

This table summarizes the <em>valence eletronic structure </em>of the representative elements:

<u>Period (column)    name         number of valence eletrons    Structure</u>

1                        Alkali metals                             1                             ns¹

2                       Alkaline earth metals               2                            ns²

13                                                                        3                            ns² np¹

14                                                                        4                            ns² np²                                          

15                      Pnictogens                               5                             ns² np³                                                                                        

16                      Chalcogens                              6                             ns² np⁴

17                      Halogens                                  7                             ns² np⁵

18                      Noble gases                             8                            ns² np⁶

There you can see that the <em>halogens</em> belong to the period 17, have 7 valence electrons, and their<em> valence electrons are have the structure ns² np⁵.</em>

This is the specific valence electronic structure for the first five halogens:

<u>Halogen      atomic number      row (n)   period   valence electronic structure</u>

Fluor               9                             2            15                  2s² 2p⁵

Chlorine        17                             3            15                  3s² 3p⁵

Bromine        35                            4            15                  4s² 4p⁵

Iodine            53                            5            15                  5s² 5p⁵

Astatine        85                            6             15                 6s² 6p⁵

There you see the common <em>structre ns² np⁵.</em>

8 0
4 years ago
How many gallons of a 60​% antifreeze solution must be mixed with 70 gallons of 25​% antifreeze to get a mixture that is 50​% ​a
Neporo4naja [7]

Answer:

The answer to your question is 175 gallons

Explanation:

Data

60% antifreeze solution  volume = ? = x

25% antifreeze solution   volume = 25%

Final concentration 50%

Process

              0.6x + 0.25(70) = 0.5(70 + x)

Simplification

              0.6x + 17.5 = 35 + 0.5x

              0.6x - 0.5x = 35 - 17.5

                          0.1x = 17.5

                              x = 17.5/0.1

Result

                              x = 175 gallons

6 0
4 years ago
a student is asked to prepare 75.0 ml of a 130M solution of HF using a 2.000M standard solution. Calculate the volume in mL of 2
Blizzard [7]

Answer:

Volume required from standard solution = 4675 mL

Explanation:

Given data:

Final volume = 75.0 mL

Final molarity = 130 M

Molarity of standard solution = 2.000 M

Volume required from standard solution = ?

Solution:

We use the formula,

C₁V₁ = C₂V₂

here,

C₁ = Molarity of standard solution

V₁ = Volume required from standard solution

C₂ = Final molarity

V₂ = Final volume

Now we will put the values in formula,

C₁V₁ = C₂V₂

2.000 M × V₁ = 130 M × 75.0 mL

V₁  = 9750 M. mL / 2.000 M

V₁  = 4675 mL

5 0
4 years ago
Which part of a star does the star’s energy come from?
Paraphin [41]

Answer:

For most of its active life, a star shines due to thermonuclear fusion of hydrogen into helium in its core, releasing energy that traverses the star's interior and then radiates into outer space. At the end of a star's lifetime, its core becomes a stellar remnant : a white dwarf , a neutron star , or, if it is sufficiently massive, a black hole .

Explanation:

4 0
3 years ago
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The Periodic Table is organized into or by _________________. A. All of these B. Groups C. Increasing atomic number D. Propertie
il63 [147K]

Answer:

My best bet is to go with A. All of these

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3 years ago
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