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Vlad1618 [11]
3 years ago
13

How is the air in tube 4 kept out of contact with the nail​

Chemistry
1 answer:
klasskru [66]3 years ago
7 0

Answer:

If you ever wonder why nails rust, it's because rusting happens when a metal is exposed to oxygen. The molecules of iron on the surface of the nail exchange atoms with the oxygen in the air and produce a new substance, the reddish-brown ferrous oxide, a.k.a. rust.

Explanation:

please mark this answer as brainliest

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A decomposition reaction, with a rate that is observed to slow down as the reaction proceeds, has a half-life that does not depe
mr_godi [17]

Answer: A plot of the natural log of the concentration of the reactant as a function of time is linear.

Explanation:

Since it was explicitly stated in the question that the half life is independent of the initial concentration of the reactant then the third option must necessarily be false. Also, the plot of the natural logarithm of the concentration of reactant against time for a first order reaction is linear. In a first order reaction, the half life is independent of the initial concentration of the reactant. Hence the answer.

3 0
3 years ago
How do lawmakers make good environmental decisions??
Sliva [168]
<h2>Answer : By weighing the costs and benefits of an environmental issue </h2><h3> Explanation :</h3>

The law makers usually conduct many studies before a law is imposed. They try to explore many other options available to the current environmental issue and then come to a conclusion to make a law.

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4 0
2 years ago
Polyatomic ions
Vitek1552 [10]
I believe the answer is A.
5 0
3 years ago
The pressure of a sample of helium in a 200. ml container is 2.0 atm. If the helium is compressed to a pressure of 40. atm witho
Crank

Answer:

V_2=10mL

Explanation:

Hello there!

In this case, according to the given information, it will be possible for us to solve this problem by using the Boyle's law as an inversely proportional relationship between pressure and volume:

P_2V_2=P_1V_1

In such a way, we solve for the final volume, V2, and plug in the initial volume and pressure and final pressure to obtain:

V_2=\frac{P_1V_1}{P_2} \\\\V_2=\frac{2.0atm*200.mL}{40.atm}\\\\V_2=10mL

Regards!

5 0
3 years ago
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