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Yakvenalex [24]
2 years ago
11

3. A representation of one unit of KCl in water is shown below. (The water molecules are intentionally not shown.)

Chemistry
1 answer:
alukav5142 [94]2 years ago
7 0

The representation is showing potassium atom (K) and Chlorine atom (Cl) when it ought to show their ions i.e potassium ion (K⁺) and Chlorine ion (Cl¯)

<h3>Dissociation equation for KCl</h3>

When potassium chloride, KCl dissolves in water, it dissociate to produce potassium ion (K⁺) and Chlorine ion (Cl¯) as shown below:

KCl(aq) —> K⁺(aq) + Cl¯(aq)

The representation given in the question is only showing potassium atom (K) and Chlorine atom (Cl). This makes it wrong as dissolution of ionic compounds in water will results in the corresponding ions of the element that makes up the compound

Please see attached photo

Learn more about dissociation equation:

brainly.com/question/25854432

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(GIVING BRAINLIEST)Match the type of chemical bond with the best description:
Kipish [7]

Answer:

A and 3

B and 2

C and 1

Explanation:

<em>Ion</em>ic bonding is the transfer of electrons from a cat<em>ion</em> to an an<em>ion</em>.

Covalent bonding is the sharing of electrons between nonmetal atoms.

<em>Metallic</em> bonding is the sea of electrons <em>metal </em>cations.

Hope this helped!

8 0
3 years ago
Determine the heat needed to warm 25.3 g of copper from 22 degrees celsius to 39 degrees celsius.
Serggg [28]

Answer:

The heat needed to warm 25.3 g of copper from 22°C to 39°C is 165.59 Joules.

Explanation:

Q=mc\Delta T

Where:

Q = heat absorbed  or heat lost

c = specific heat of substance

m = Mass of the substance

ΔT = change in temperature of the substance

We have mass of copper = m = 25.3 g

Specific heat of copper = c = 0.385 J/g°C

ΔT  = 39°C - 22°C = 17°C

Heat absorbed by the copper :

Q=25.3 g\times 0.385 J/g^oC\times 17^oC=165.59 J

The heat needed to warm 25.3 g of copper from 22°C to 39°C is 165.59 Joules.

5 0
3 years ago
How many moles are in 5.03 x 1023 molecules?
AlladinOne [14]

Answer:

Some formulas for calculating mole are

Mole = Mass/ Molar mass

Mole = no of particles / avogadros constant

NB : no of particles can be no of atoms , no of ions , or no of molecules 2. Avogadros number or constant = 6.02 times 10 ^23

so we will be using the second formula

Mole = no of particles / avogadros constant

Mole =  5.03 x 10 ^23/6.02 x10^23

Mole = 8.355x10^45

hope it helps :)

Explanation:

4 0
3 years ago
You
Igoryamba

Answer:

The arm that was not sprayed with anything

Explanation:

The control group would be <u>the arm that was not sprayed with anything</u>.

<em>The control group during an experiment is a group that forms the baseline for comparison in other to determine the effects of a treatment. The control group does not include the variable that is being tested and as such, it provides the benchmark to measure the effects of the tested variable on the other group - the experimental group. In this case, the experimental group would be the arm that was sprayed with the repellent.</em>

8 0
3 years ago
A. CH,0, molar mass is 90 g/mol
Luba_88 [7]

what is that i cant see anything?

7 0
3 years ago
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