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riadik2000 [5.3K]
3 years ago
8

Literal Equation For my Project, Need HELP ASAP. Solve for a. Y = a (x-5)^2 + k

Mathematics
1 answer:
Charra [1.4K]3 years ago
6 0

Answer:

the vertex is (h,k). This is the lowest point of the parabola

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slava [35]
First one is 70 degrees
5 0
2 years ago
Read 2 more answers
in a AP the first term is 8,nth term is 33 and sum to first n terms is 123.Find n and common difference​
allsm [11]

I believe there is no such AP...

Recursively, this sequence is supposed to be given by

\begin{cases}a_1=8\\a_k=a_{k-1}+d&\text{for }k>1\end{cases}

so that

a_k=a_{k-1}+d=a_{k-2}+2d=\cdots=a_1+(k-1)d

a_n=a_1+(n-1)d

33=8+(n-1)d

21=(n-1)d

n has to be an integer, which means there are 4 possible cases.

Case 1: n-1=1 and d=21. But

\displaystyle\sum_{k=1}^2(8+21(k-1))=37\neq123

Case 2: n-1=21 and d=1. But

\displaystyle\sum_{k=1}^{22}(8+1(k-1))=407\neq123

Case 3: n-1=3 and d=7. But

\displaystyle\sum_{k=1}^4(8+7(k-1))=74\neq123

Case 4: n-1=7 and d=3. But

\displaystyle\sum_{k=1}^8(8+3(k-1))=148\neq123

8 0
3 years ago
Help did i get this answer right
4vir4ik [10]
I do believe it would be a 2.2 

3 0
3 years ago
write an equation in slope intercept form for the line that passes through the point, and is perpendicular to the line y=-1/3x+9
aleksklad [387]

Answer:

Step-by-step explanation:

y=-1/3x+9

This is written in the format y=mx+b, where m is the slope and b the y-intercept (the value of y when x=0).

Perpendicular lines have a slope that is the negative inverse of the slope of the reference line, in this case -(1/3).  The new slope is 3.  equation is:

y = 3x + b

To find b, enter the given point, (-6,-2) and solve for b:

y = 3x + b

-2 = 3(-6) + b

-2 = -18 + b

b = 16

The full equation is y=3x + 18

8 0
2 years ago
2x-ay=3<br><br>8x-12y=b I'm supposed to find what a-b equals.
PolarNik [594]

Answer:

2

Step-by-step explanation:

3 0
3 years ago
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