Answer - D.
you basically find the equation of the line first and eliminate the wrong answers...
Strategy: before u do any of this, label your coordinates as (X1,Y1) and (X2,Y2) and u can choose any of ur points to be as x1 or x2 or y1 or y1...
basically, I'll choose (6,7) as (x1,y1) and (2,-1) as (x2,y2). SO,
First you have to find the gradient (m) of the line.
you do this by using the formula m = Y2-Y1 / X2-X1 (where '/' is division sign) ....
Put the numbers in their respective places and your gradient will be 2x. we put the x after our number to represent it as a gradient as the straight line formula is y = mx+c and you've found the m.
NOW.
use the formula Y-Y1=m(x-x1) to find the equation of the line.Again u can use any Y1 and X1 here but remember your m is 2
replace the digits and solve...Hopefully you'll get sth like this if you use the points (6,7):
Y-7 = 2(x-6) ....
y=2x-12+7...
Y=2x-5! <<<< this is your straight line equation!
Now all u gotta do is rearrange all your options into y = mx+c.
D. is incorrect as it gives us y=2x+5 and not y = 2x-5 unlike the others
Hope you get it!
Answer:
Triangle rsu = Triangle tus
Statements Reasons
UR ≅ TS Definition of Rectangle
US ≅ US Reflexive Property
<U, <T, <R, <S are all congruent and right angles
Definition of Rectangle
ΔRSU ≅ ΔTUS Side, Angle, Side
UR ≅ TS CPCTC
Just draw a reverse angle,hence you get comparison.
So, satisfying S-S-S
RUS ≅ SUT
RSU ≅ TUS
So, angle
URS = angle TUS
2. Pythagoras Theorem
Triangle RUS
A^2 + B^2 = C^2
Uu^2 + Ss^2 = Rr^2
√Rr = Rr^2 = x
Triangle TUS
A^2 + B^2 = C^2
Ss^2 + Uu^2 = Tt^2
√Tt = Tt^2 = x
UR measure / sin (60) x (90) = US measure.
ST measure / sin (60) x (90) = US measure.
Proves angles RSU = 30 degree
Proves angles TUS = 30 degree
As all adjacent angles in a triangle add up to 180 degree.
Answer:
x = 50
Step-by-step explanation:
You are correct.
x + m<PQS + m<PSQ = 180
m<PQS = m<QRT = 70
m<QST + m<PSQ = 180
120 + m<PSQ = 180
m<PSQ = 60
x + 70 + 60 = 180
x + 130 = 180
x = 50
Great job!
Answer:
$1002
Step-by-step explanation:
The answer could not be submitted;
So, I added it as an attachment
