To have 2 real number solutions the discriminant b^2 - 4ac must be greater than zero.
so the condition for 2 real roots in this equation is:-
b^2 - 4*1*5 > 0
b^2 > 20
b > sqrt 20 ( positive root) Answer
Answer:
x=-3
Y=-5
Step-by-step explanation:
2x-y=-1 ×2
3x-2y=1. ×1
4x-2y= -2
3x-2y=1
eliminate y by subtracting
Hello from MrBillDoesMath!
Answer:
1/2
Discussion:
6/12 = => as 12 = 6*2
6 /( 6*2) = => cancel 6's in num and denom.
1/2
Thank you,
MrB
Answer: -29.3
Step-by-step explanation: -7y + 2x
-7(-6.3) + 2(-7.4) = -29.3
