All categories

2 years ago

How many unique ways are there to arrange the letters in the word APE

Mathematics

2 answers:

CaHeK987 [17]2 years ago

6 0

Answer: 9

Step-by-step explanation:

makvit [3.9K]2 years ago

3 0

Answer:

Step-by-step explanation:

So there are 2 ways to do this.

The first one is to actually just rearrange the letters as many ways as possible. So here's this method:

1. APE

2. AEP

3. PAE

4. PEA

5. EAP

6. EPA

So this method is fine when you just have 3 letters but once you get to more and more letters this becomes close to impossible to do. That's why we use the second method: factorials. When all of the letters in the word are different the equation is really simple. Since the word APE has 3 letters your equation will be 3!

[Mini lesson time!!!

What the happy little exclamation point does means is that you should take the number in front of it and multiply it by all of the numbers that come before it.]

So lets solve this now:

3!=x

1·2·3=x

6=x

(Once again... this method only works if all of the letters in the word are DIFFERENT. For example if you had the word FUNNEST, you would use a different equation because there are 2 of the letter 'N'.)

If anything I've said is confusing or you need any other help just let me know!!

You might be interested in

The sum of twice a number and 13 is 75 • but in an algebraic equation DONT SOLVE

Alchen [17]

Answer:

I won't solve it, because you asked me to.

Step-by-step explanation:

The first question we should ask ourselves is "what are we looking to solve?"

We are looking for some sort of value that satisfies that equation. We'll call it x

Reading from left to right:

The sum of twice a number and 13 is 75

+ 2 x 13 = 75

2x + 13 = 75

5 0

2 years ago

Ok so Ive been having trouble with Math can anyone help??

Illusion [34]

For the first bit, put $930 + 7.5x and the second part is 58,000, 930 x 7.5 x 8

6 0

2 years ago

Carleen has 104 pieces of candy leftover from Halloween. She would like to distribute them evenly to the 8 kids on her block. Wr

algol13

Answer:

8x = 104

x = 13

Step-by-step explanation:

Since we are trying to distribute it evenly, we divide 104 by 8 to get 13 pieces of candy per child.

The equation is saying 8 kids times x amount of candy per kid is equal to a total amount of 104 pieces of candy.

4 0

2 years ago

Read 2 more answers

Given vectors u = (−1, 2, 3) and v = (3, 4, 2) in R 3 , consider the linear span: Span{u, v} := {αu + βv: α, β ∈ R}. Are the vec

julia-pushkina [17]

Answer:

$(2,6,6) \not \in \text{Span}(u,v)$

$(-9,-2,5)\in \text{Span}(u,v)$

Step-by-step explanation:

Let $b=(b_1,b_2,b_3) \in \mathbb{R}^3$ . We have that $b\in \text{Span}\{u,v\}$ if and only if we can find scalars $\alpha,\beta \in \mathbb{R}$ such that $\alpha u + \beta v = b$ . This can be translated to the following equations:

1. $-\alpha + 3 \beta = b_1$

2. $2\alpha+4 \beta = b_2$

3. $3 \alpha +2 \beta = b_3$

Which is a system of 3 equations a 2 variables. We can take two of this equations, find the solutions for $\alpha,\beta$ and check if the third equationd is fulfilled.

Case (2,6,6)

Using equations 1 and 2 we get

$-\alpha + 3 \beta = 2$

$2\alpha+4 \beta = 6$

whose unique solutions are $\alpha =1 = \beta$ , but note that for this values, the third equation doesn't hold (3+2 = 5 $\neq$ 6). So this vector is not in the generated space of u and v.

Case (-9,-2,5)

Using equations 1 and 2 we get

$-\alpha + 3 \beta = -9$

$2\alpha+4 \beta = -2$

whose unique solutions are $\alpha=3, \beta=-2$ . Note that in this case, the third equation holds, since 3(3)+2(-2)=5. So this vector is in the generated space of u and v.

4 0

2 years ago

hjlf

Idkhzslkkxkfof?&$ask a another girl for that answer

3 0

2 years ago