All categories

2 years ago

Please help

Mathematics

1 answer:

shtirl [24]2 years ago

4 0

Answer:

Step-by-step explanation:

The slope of the line in question is the same as the slope of the line parallel to it. Using y = mx + b, where m is the slope, we find the slope of our line is -3.

Using the pt-slope form, y - y1 = m( x - x1), we get y - (-1) = -3( x - 2) or y + 1 = -3x + 6. Which leads us to y = -3x + 5. QED

You might be interested in

Answer #1,3,4,5,6,and 7

Fofino [41]

Can you type the answers in plz. I can't see the pic

7 0

3 years ago

What is the range of the function y=3^x x>0 R y<0 y>0

Dima020 [189]

Answer:

The range is y > 0

Step-by-step explanation:

3^x is always greater than 0 and cannot be negative unless x is not real

5 0

3 years ago

Hank bought 5 CDs for $64.75. If each CD cost the same price, how much did each cost?

dem82 [27]

64.75/5= $12.96

you simply divide 64.75 by 5

6 0

2 years ago

What is the area of the pyramid square base

Scrat [10]

Answer:

25 cm^2

Step-by-step explanation:

the area of 1 triangle is 20, so the missing length of the triangle is 5. 5x5=25

6 0

2 years ago

Use the quadratic formula to solve the following equation -3x^2-x-3=0

tigry1 [53]

Answer:

$x=-\frac{1}{6}-\frac{\sqrt{35}}{6} i \text { and } x=-\frac{1}{6}+\frac{\sqrt{35}}{6} i$ are two roots of equation $-3 x^{2}-x-3=0$

Solution:

Need to solve given equation using quadratic formula.

$-3 x^{2}-x-3=0$

General form of quadratic equation is $a x^{2}+b x+c=0$

And quadratic formula for getting roots of quadratic equation is

$x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

In our case b = -1 , a = -3 and c = -3

Calculating roots of the equation we get

$\begin{array}{l}{x=\frac{-(-1) \pm \sqrt{(-1)^{2}-4(-3)(-3)}}{2 \times-3}} \\\\ {x=-\frac{1}{6} \pm\left(-\frac{\sqrt{-35}}{6}\right)}\end{array}$

Since $b^{2}-4 a c$ is equal to -35, which is less than zero, so given equation will not have real roots and have complex roots.

$\begin{array}{l}{\text { Hence } x=-\frac{1}{6}-\frac{\sqrt{35}}{6} i \text { and } x=-\frac{1}{6}+\frac{\sqrt{35}}{6} i \text { are two roots of equation - }} \\ {3 x^{2}-x-3=0}\end{array}$

8 0

3 years ago