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3 years ago

Factor y2 + 5y +6. (y + 1)(y + 6) (y + 2)(y + 3) (y + 2)(y + 4)

Mathematics

1 answer:

Natali5045456 [20]3 years ago

5 0

Factor y2 + 5y +6.

Multiply all of the multiple choices

(y+1)(y+6)

(y*y)(y*6)(+1*y)(+1)(+6)

y^2+6y+y+6

=y^2+7y+6

(y+2)(y+3)

(y*y)(y*3)(2*y)(2*3)

y^2+3y+2y+6

=y^2+5y+6

Answer: (y + 2)(y + 3)

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Which fractions are equivalent to 2/3

Ivenika [448]

Answer:

4/6 and 8/12 and 16/24

Step-by-step explanation:

well because it is math and math works like this basically all of theese are equal to 2/3

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3 years ago

Suppose quantity s is a length and quantity t is a time. Suppose the quantities v and a are defined by v = ds/dt and a = dv/dt.

finlep [7]

Answer:

a) $v = \frac{[L]}{[T]} = LT^{-1}$

b) $a = \frac{[L}{T}^{-1}]}{{T}}= L T^{-1} T^{-1}= L T^{-2}$

c) $\int v dt = s(t) = [L]=L$

d) $\int a dt = v(t) = [L][T]^{-1}=LT^{-1}$

e) $\frac{da}{dt}= \frac{[L][T]^{-2}}{T} = [L][T]^{-2} [T]^{-1} = LT^{-3}$

Step-by-step explanation:

Let define some notation:

[L]= represent longitude , [T] =represent time

And we have defined:

s(t) a position function

$v = \frac{ds}{dt}$

$a= \frac{dv}{dt}$

Part a

If we do the dimensional analysis for v we got:

$v = \frac{[L]}{[T]} = LT^{-1}$

Part b

For the acceleration we can use the result obtained from part a and we got:

$a = \frac{[L}{T}^{-1}]}{{T}}= L T^{-1} T^{-1}= L T^{-2}$

Part c

From definition if we do the integral of the velocity respect to t we got the position:

$\int v dt = s(t)$

And the dimensional analysis for the position is:

$\int v dt = s(t) = [L]=L$

Part d

The integral for the acceleration respect to the time is the velocity:

$\int a dt = v(t)$

And the dimensional analysis for the position is:

$\int a dt = v(t) = [L][T]^{-1}=LT^{-1}$

Part e

If we take the derivate respect to the acceleration and we want to find the dimensional analysis for this case we got:

$\frac{da}{dt}= \frac{[L][T]^{-2}}{T} = [L][T]^{-2} [T]^{-1} = LT^{-3}$

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3 years ago

If g(x)=2x-1 and h(x)= swuare root x, find (g o h) (9)

AnnZ [28]

Answer:

Step-by-step explanation:

To evaluate (g ￮ h)(9), evaluate h(9) , then use this value to evaluate g(x)

h(9) = $\sqrt{9}$ = 3, then

g(3) = 2(3) - 1 = 6 - 1 = 5

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3 years ago

What is the perimeter of the parallelogram?<br> Please help! Will mark brainlyest.

Luba_88 [7]

Answer:

Step-by-step explanation:

B=base

A=side

X=2(a+b)=2·(13+16)=58

3 0

2 years ago

Read 2 more answers

An amount of $23,000 is borrowed for 11 years at 6.75% interest, compounded annually. If the loan is paid in full at the end of

Pavel [41]

Answer:

Given that,

An amount of $23,000 is borrowed for 11 years at 6.75% interest, compounded annually.

To find the Amount paid back after 11 years.

Explanation:

we know that,

The formula to find the,

Amount after n years of interest rate r% compounded annually is,

$A=P(1+\frac{r}{100})^n$

where P is the initial amount.

Here, we have that,

P=$23,000

r=6.75

n=11

Substitute the values we get,

$A=23000(1+\frac{6.75}{100})^{11}$

Solving this we get,

$A=23000(1+0.0675)^{11}$ $A=23000(1.0675)^{11}$ $A=23000(2.05138)$ $A=47181.805$

Round to the nearest dollar.

$A=47181.805\approx47182$

Answer is: Amount paid back is $47182 after 11 years

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1 year ago