Answer and Explanation:
The computations are as follows
a. For basic earning per share
= Net income ÷ Average number of outstanding common shares
= ($16,888 - $1,483) ÷ 10462.282 shares
= $1.47 per share
b. Preferred stock dividends = Net income - Net income applicable to common shareholders
= $4,833 - $4,211
= $622
c. The net income applicable to common shareholders is
= Average number of common shares outstanding × Basic earning per share
= 10,527.818 × $0.40
= $4,211
d. The net income is
= Preference stock dividend + Net income applicable to common shareholders
= $1,349 + $10,583
= $11,932
e. Average number of common shares outstanding is
= Net income for common shareholders ÷ basic earning per share
= $10,583 ÷ $0.94
= $11,258.51
We simply applied the general formulas
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a. Based on the information given the revised depreciation is:
Building $1,250
Warehouse $5,993
b. Debit Depreciation expense $13,375
Credit Accumulated depreciation-Building $13,375
a. Victor Mineli Revised depreciation
Revised depreciation for Building
Building= ($700,000-$129,900-$35,100)/40
Building= $535,000/40
Building=$13,375
Revised depreciation for Warehouse
Warehouse=($115,000-$22,100-$3,000)/15
Warehouse =$89,900/15
Warehouse=$5,993
b. Journal entry
Debit Depreciation expense $13,375
Credit Accumulated depreciation-Building $13,375
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Answer:
a, 22276.07
b. $32.9157 million
c.$29.9669million
Explanation:
Find the values of k and a assuming a relationship of the form Assume that f(y)=ky^a is in units of barrels per day.


b. Determine the optimal timing of plant additions and the optimal size and cost of each plant addition.a=0.8073, rx=0.41
optimal timing x=rx/r=2.05yrs
optimal size xD=2.05(1.5)
3.075million barrels/year

$32.9157 million
c. Suppose that the largest single refinery that can be built with current technology is 7,500 barrels per day. Determine the optimal timing of plant additions and the optimal size and cost of each plant in this case
Optimal size xD=min
Optimal timing will be X^*=x*D/D=2.7375/1.5=1.825 year
optimal cost f(y)=ky^a=0.0223(7500)^0.8073=$29,9669 milion