Use the formula or complete the square.
The zeroes of the quadratic can be real and rational; real and irrational; complex conjugates.
If the quadratic is ax²+bx+c, x=(-b+√b²-4ac)/2a.
If b² > 4ac the solutions are real. If b²-4ac is a perfect square, the solutions are real and rational; otherwise they’re real but irrational.
If b² < 4ac the solutions are complex.
You have the correct chosen
Answer:
The given table DOES NOT represent a linear function as there is NO CONSTANT change in x and y values.
Step-by-step explanation:
Given the table
x -10 -14 -18 -24
y 6 10 16 24
- A linear function has a constant change in x and a constant change in y values.
In order to determine whether the table represents the linear function or not, we need to check whether there is constant change in x and y.
It is clear that there is a NO constant change in x
i.e. -14-(-10) = -4, -18-(-14) = -4, -24-(-18) = -6
It is clear that there is a NO constant change in y
i.e. 10-6=4, 16-10 = 6, 24-16 = 8
Therefore, the given table DOES NOT represent a linear function as there is NO CONSTANT change in x and y values.
Answer:
eight hundred thirty-one billion seventy-five million two hundred eighty thousand four hundred ninety-six
Step-by-step explanation: