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leva [86]
2 years ago
7

Evaluate the equation h - 3/5 = 13/45

Mathematics
1 answer:
blsea [12.9K]2 years ago
8 0

Answer:

The choice A. h = 8/9

Step-by-step explanation:

h -  \frac{3}{5}  =  \frac{13}{45}  \\  \\ h =  \frac{13}{45}  +  \frac{3}{5}  \\  \\ h =  \frac{13}{45}  +  \frac{27}{45}  \\  \\ h =  \frac{40}{45}  =  \frac{8}{9}

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What is the best estimate for 56.23 - 45.9?<br> A. 9<br> B. 10<br> C. 11<br> D. 15
DIA [1.3K]

Answer:

10 Letter B

Step-by-step explanation:

56.23 rounds down to 56 and 45.9 rounds up to 46. So 56 - 46 = 10

5 0
2 years ago
A hair salon in Cambridge, Massachusetts, reports that on seven randomly selected weekdays, the number of customers who visited
morpeh [17]

Answer:

a: 28 < µ < 34

Step-by-step explanation:

We need the mean, var, and standard deviation for the data set.  See first attached photo for calculations for these...

We get a mean of 222/7 = 31.7143

and a sample standard deviation of: 4.3079

We can now construct our confidence interval.  See the second attached photo for the construction steps.

They want a 90% confidence interval.  Our sample size is 7, so since n < 30, we will use a t-score.  Look up the value under the 10% area in 2 tails column, and degree of freedom is 6 (degree of freedom is always 1 less than sample size for confidence intervals when n < 30)

The t-value is: 1.943

We rounded down to the nearest person in the interval because we don't want to over estimate.  It said 28.55, so more than 28 but not quite 29, so if we use 29 as the lower limit, we could over estimate.  It's better to use 28 and underestimate a little when considering customer flow.

5 0
3 years ago
Suppose lines EF and GH are reflected over the line Y equals X to form the lines JK and LM which statement would be true about t
katrin [286]

Answer:

A) JK and LM will be parallel to each other.

Step-by-step explanation:

On reflection on y=x line the x co-ordinate changes with y co-ordinate and y co-ordinate changes with x co-ordinate

(x,y)\rightarrow (y,x)

Points on line EF

(0,6) , (-5,-2)

On reflection of this line on y=x the new points we get for line JK are

(6,0),(-2,-5)

Points on line GH

(-4,9),(-9,1)

On reflection on y=x line the new points we get for line LM are

(9,-4),(1,-9)

Slope of line JK

m=\frac{y_2-y_1}{x2-x1}\\m=\frac{(-5)-0}{(-2)-6} \\m=\frac{-5}{-8}=\frac{5}{8}

Slope of line LM

m=\frac{y_2-y_1}{x2-x1}\\m=\frac{(-9)-(-4)}{1-9} \\m=\frac{-9+4}{-8}=\frac{-5}{-8}\\m=\frac{5}{8}

For two line to be parallel, their slopes will be same.

m_{JK} =\frac{5}{8} , m_{LM}=\frac{5}{8}

Since slopes of lines JK and LM are same therefore we can say that these are parallel to each other.

5 0
3 years ago
Factor:<br> 4b2 - 12b + 9
Vikentia [17]

Answer:

  (2b-3)²

Step-by-step explanation:

The square of a binomial is ...

  (p - q)² = p² - 2pq + q²

The fact that the first and last terms are perfect squares suggests that you might want to look to see if the middle term matches this form. It does.

For p² = 4b², p=2b.

For q² = 9, q = 3.

Then 2pq = 2(2b)(3) = 12b.

So, the factoring is ...

  4b² -12b +9 = (2b -3)²

5 0
3 years ago
Reduce in standard form -3/-15​
andriy [413]

Answer:

1/5? 0.2?

Step-by-step explanation:

5 0
2 years ago
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