Answer:
Option C. is correct
Step-by-step explanation:
In the triangle ABC, vertices are A(12, 8), B(4, 8) and C(4, 14)
AB =
BC =
AC =
In triangle XYZ vertices are X(6,6), Y(4,12) and Z(10, 14)
XY =
YZ =
XZ =
In triangle MNO, vertices are M(4, 16), N(4, 8) and O(-2, 8)
MN =
MO =
NO =
In triangle JKL, vertices are J(14, -2), K(12,2) and L(20, 4)
JK =
KL =
JL =
Now we compare the sides for the congruence
Since AB = MN = 8
BC = NO = 6
AC = OM = 10
So ΔABC ≅ Δ MNO
Option C. is correct
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Answer:
f(-1)=6×(-1)^-4=6/(-1)^4=6/1=6
Hello :
the terme general is : an = a1 +(n-1)d
a11 = a1+(11-1)×5
a11 = -12+50
a11 = 38
<span>the sum of the first 11 terms is : S11 = (11/2)(a1+a11)
</span>S11 = (11/2)(-12+38)
S11 = 143
Answer:
EF / LM = 1 / 4
Step-by-step explanation:
Transformation is the movement of a point from its initial location to a new location. Types of transformation are reflection, translation, dilation and rotation.
Dilation is the enlargement or reduction in the size of a figure. If a point A(x, y) is dilated by a scale factor of k, the new point is at A'(kx, ky).
Translation is the movement of a point right, left, up or down. If a point A(x, y) is translated a units left and b units down, the new point is at A'(x - a, y - b).
Translation preserves the size and shape of an object. Dilation preserves the shape but not the size.
Cdef maps to jklm with the transformation (x,y) to (4x,4y) to (x-4,y-9).
CDEF was first dilated by a scale factor of 4 to get (4x,4y) before it was translated by (x-4,y-9). Since dilation changes the size of the figure, hence JKLM would be 4 times the size of CDEF. Therefore:
LM / EF = 4
EF / LM = 1 / 4
