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3 years ago

Plzzzz HELPPPP!!!!!!!

Chemistry

2 answers:

yulyashka [42]3 years ago

7 0

Explanation:

Seems to me like you have 8H and 2N. You need 3H for every N so 6H total. 8H-6H=2H which is one molecule of H2.

Marysya12 [62]3 years ago

4 0

Explanation:

one molecule of H2 I think

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Could someone help me with this?

Varvara68 [4.7K]

Solving part-1 only

KMnO_4

Transition metal is Manganese (Mn)

Actually it's the oxidation number of Mn

Let's find how?

$\\ \tt\Rrightarrow x+1+4(-2)=0$

$\\ \tt\Rrightarrow x+1-8=0$

$\\ \tt\Rrightarrow x-7=0$

$\\ \tt\Rrightarrow x=+7$

x is the oxidation number

Purple as per the color of potassium permanganate

$\boxed{\begin{array}{c|c|c}\boxed{\bf Tube} &\boxed{\bf Charge} &\boxed{\bf No\:of\; electrons\: loss}\\ \sf 2 &\sf +6 &\sf 6e^-\\ \sf 3& \sf +2 &\sf 2e- \\ \sf 4 &\sf 4 &\sf 4e^-\end{array}}$

7 0

2 years ago

The first excited vibrational energy level of diatomic chlo- rine (Cl2) is 558 cm^-1 above the ground state. Wave- numbers, the

Usimov [2.4K]

Answer:

The answer is "0.0000190 and 2.7 J".

Explanation:

$\to P_4=\frac{e^{-\beta}(4+\frac{1}{2}) hev}{2vb}\\\\$

$=\frac{e^{-9(1.35)}}{0.278v}\\\\=\frac{e^{-12.5}}{0.278}\\\\=\frac{0.000005285}{0.278}\\\\=0.0000190$

Given:

$h=6.626 \times 10^{-34}\\\\c=3\times 10^{10}\\\\v=558\ cm^{-1}\\\\K=1.38 \times 10^{-23}\\\\ T=298\\\\$

$E=\frac{hcv}{KT}\\\\$

by putting the value into the above formula so, the value is 2.7 J

6 0

3 years ago

suppose you want to do an experiment to hear how three different objects would sound when you dropping them the same distance. y

hodyreva [135]

The variable would be the distance you dropped them.

8 0

3 years ago

Write a balanced equation for the reaction of Na₂S and CdSO₄. Express your answer as a chemical equation. Identify all of the ph

Luba_88 [7]

Explanation:

A chemical reaction equation that contains same number of atoms on both reactant and product side is known as a balanced chemical reaction equation.

For example, $Na_{2}S(aq) + CdSO_{4}(aq) \rightarrow Na_{2}SO_{4}(aq) + CdS(s)$

Here, number of reactant molecules are as follows.

Na = 2

S = 2

Cd = 1

O = 4

Number of product molecules are as follows.

Na = 2

S = 2

Cd = 1

O = 4

As there are already equal number of atoms on both reactant and product side. Hence, the reaction equation is balanced.

Also, in this reaction both $Na_{2}S$ and $CdSO_{4}$ are present as aqueous solution. And, CdS is the precipitate that is formed as it is the insoluble solid that forms.

$Na_{2}SO_{4}$ is present in aqueous state.

3 0

3 years ago

I'm sorry for asking so many questions this assignment is past due and I need it done NOW

marishachu [46]

Answer:

7N to the right

Explanation:

7 0

2 years ago