Answer:1.
1.Balanced equation
C4H10 + 9 02 ==> 5H20 +4CO2
2. Volume of CO2 =596L
Explanation:
1.Combustion of alkane is the reaction of alkanes with Oxygen. And the general equation for the combustion is;
CxHy +( x+y/4) O2 ==> y/2 02 + xCO2
Where x and y are number of carbon and hydrogen atoms respectively.
For butane (C4H10)
x=4 and y=10
Therefore
C4H10 + 9 02 ==> 5H20 +4CO2
2. Mass of butane = 0.360kg
Molar mass of C4H10 = ( 12×4 + 1×10)
= 48 +10=58g/mol= 0.058kg/mol
Mole = mass/molar mass
Mole = 0.360/0.058= 6.2moles
From the stoichiometric equation
1mole of C4H10 will gives 4moles of CO2
Therefore
6.2moles of C4H10 will gives 4 moles of 24.8 moles of CO2
Using the ideal gas equation
PV=nRT
P= 1.0atm
V=?
n= 24.8mol.
R=0.08206atmL/molK
T=20+273=293
V= 24.8 × 0.08206 × 293
V= 596L
Therefore the volume of CO2 produced is 596L
Solids have a solid, fixed shape, while liquids can change shape as they are put into a different container or cup. Gases also take the shape of the object they are in.
It will have 27 neutrons and protons because the atomic number is the same as the number of neutrons and protons.
Answer:
Two
Step-by-step explanation:
In <em>multiplication problems</em>, your answer can have no more significant figures than the number with the <em>fewest significant figures</em>.
Start with the calculation inside parentheses:
5.1 × 10.6 = 54.060 000 00 (by my calculator)
There are three significant figures in 10.6, but only two in 5.1.
In this were a number you had to report, you would round to <em>two</em> significant figures and report the answer as 54.
54.060 000 00 → 54 (to two significant figures)
However, you must multiply this intermediate answer by 2.524.
Therefore, you multiply the number in the calculator by 2.524 and get
54.060 000 00 × 2.524 = 136.447 4400
<em>NOW</em>, you round to two significant figures and report the answer as <em>140</em>.
