Question

g Calculate the [OH-] from the results of your titrations. Explain your calculations2. Calculate the [Ca2+]. Explain your calculations3. Calculate the Ksp for calcium hydroxide. Explain your calculations4. Temperature affects equilibrium in one direction or the other (depending on whether the system is Exo or Endothermic). Discuss5. What does the value of Ksp tell you in terms of equilibrium?6. The theoretical value for Ksp of Ca(OH)2 at 25°C is 9.0 X 10-6, compare and suggest reasons for the difference.

Answer 1

Answer:

Explanation:

*Since the titration is between the strong acid HCl and the strong base Ca(OH)2, the pH at the equivalent point should be 7. On interpolation, we will obtain that 9.50mL and 9.82 mL of HCl is required to completely neutralized the given Ca(OH)2 solution.

*pH at the equivalence point =7

we know that pH + pOH = 14

Hence pOH= 14-7=7

pOH= -log(OH-)

The concentration of OH-= 10-pH= 1X10-7 M

One reason for the low solubility may be the higher reaction temperature, Another reason is the common ion effect.