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3 years ago

Rewrite x^2+12x+42 in the form (x+b)^2 +c

Mathematics

1 answer:

Rzqust [24]3 years ago

6 0

This is completing the square:

(x^2+12x+36)+42-36

Answer: (x+6)^2 +6

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polet [3.4K]

Answer:this is a little late but i think its 0.4

Step-by-step explanation:

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3 years ago

Read 2 more answers

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astra-53 [7]

Answer:

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3 years ago

A planned community has 150 homes, each with an automatic garage door opener. The door opener has seven switches that a homeowne

alexdok [17]

Answer:

The probability that at least two homeowners will set their switches to the same code is 100%.

Step-by-step explanation:

Consider the provided information.

The total number of code can be set with 0 or 1 is:

2×2×2×2×2×2×2=128

There are 128 different codes.

The probability that code is unique is 1/128

Now, the probability that all codes are unique is:

$[\frac{1}{128}]^{150}$

Hence, the probability that all the codes are not unique is:

$1-[\frac{1}{128}]^{150} \approx 1$

Because the value of $[\frac{1}{128}]^{150}$ is very small

As they can set 128 different codes and there are 150 homes. So, at least two homeowners will set their switches to the same code is 100%.

Hence, the probability that at least two homeowners will set their switches to the same code is 100%.

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3 years ago

How do you solve the equation F = 9/5(K - 273.15) + 32 when you're solving for K?

Mumz [18]

$\displaystyle\\Answer:\ K=\frac{5}{9}(F-32^0)+273.15^0$

Step-by-step explanation:

$\displaystyle\\F=\frac{9}{5} (K-273.15)+32\\F-32=\frac{9}{5} (K-273.15)+32-32\\F-32=\frac{9}{5} (k-273.15)\\Multiply\ both\ parts\ of\ the\ equation\ by\ \frac{5}{9} \\(\frac{5}{9})(F-32)=\frac{9}{5} (K-273.15)(\frac{5}{9} )\\\\\frac{5}{9} (F-32)=K-273.15\\\\\frac{5}{9} (F-32)+273.15=K-273.15+273.15\\\\\frac{5}{9} (F-32)+273.15=K$

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2 years ago

If 4x + b = 12, then x is equal to:

vlabodo [156]

Answer:

4x + 12 = 24

Subtract 12 to both sides

4x + 12 - 12 = 24 - 12

4x = 12

Divide 4 to both sides

4x ÷ 4 = 12 ÷ 4

x = 3

Step-by-step explanation:

3 0

3 years ago