The standard form of a hyperbola is <span><span><span>x2/</span><span>a2 </span></span>− y<span><span>2/ </span><span>b2 = 1
the tangent line is the first derivative of the function</span></span></span><span>y′ = <span>b^2x/ a^2 y
hence the slope is </span></span><span>m = <span>b^2 x0 / <span>a^2 <span>x1
</span></span></span></span>Therefore the equation of the tangent line isy−x1 = b^2 x0 / a^2 x1* (x−x0)
Step-by-step explanation:
7 - 3b-2(0 + 3 - 2b)
To simplify the expression in the box, Fatua used
these steps:
Step 1:7 - 3b-2(3 - 3b)
Step 2:7 - 3-6-36-
Step 3: -13 - 66
Did Fatua calculate correctly? if nnot, in what step
did she make her FIRST mistake?
A parallel line to y = -3x+7 with a y intercept of 0 is
y = -3x + 0, or you could simply write it as y = -3x
Answer:
Step-by-step explanation:
LM=2x+24
MN= x+28
LN=31
LN=(2x+24)+(x+28)
31=(2x+24)+(x+28)
solve
31=(2x+24)+(x+28)
31-24-28 = 2x +x
-21=3x
-7=x
Answer:
they are you can tell by how they aere shaped
Step-by-step explanation:
