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3 years ago

Mary worked a total of 6 1/2 hours during 5 days of work per week. What was her average workday?

Mathematics

2 answers:

spayn [35]3 years ago

8 0

Your answer is: 3. 3 hours, 18 minutes

sergij07 [2.7K]3 years ago

7 0

If you're asking if Mary worked 6 1/2 hours total out of the 5 days that it would be 1 hour and 18 minutes. If your asking how many hours she worked every day with 6 1/2 hours it would be 32 hours and 30 minutes.

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Please help with number 12

makkiz [27]

Answer:

Step-by-step explanation:

sin(195º)= -√6+√2/4

cos(195º)=-√6-√2/4

tan(195º)=2-√3

8 0

3 years ago

Read 2 more answers

Write the equation -4x^2+9y^2+32x+36y-64=0 in standard form. Please show me each step of the process!

IgorC [24]

Hey there, hope I can help!

$-4x^2+9y^2+32x+36y-64=0$

$\mathrm{Add\:}64\mathrm{\:to\:both\:sides} \ \textgreater \ 9y^2+32x+36y-4x^2=64$

$\mathrm{Factor\:out\:coefficient\:of\:square\:terms} \ \textgreater \ -4\left(x^2-8x\right)+9\left(y^2+4y\right)=64$

$\mathrm{Divide\:by\:coefficient\:of\:square\:terms:\:}4$
$-\left(x^2-8x\right)+\frac{9}{4}\left(y^2+4y\right)=16$

$\mathrm{Divide\:by\:coefficient\:of\:square\:terms:\:}9$
$-\frac{1}{9}\left(x^2-8x\right)+\frac{1}{4}\left(y^2+4y\right)=\frac{16}{9}$

$\mathrm{Convert}\:x\:\mathrm{to\:square\:form}$
$-\frac{1}{9}\left(x^2-8x+16\right)+\frac{1}{4}\left(y^2+4y\right)=\frac{16}{9}-\frac{1}{9}\left(16\right)$

$\mathrm{Convert\:to\:square\:form}$
$-\frac{1}{9}\left(x-4\right)^2+\frac{1}{4}\left(y^2+4y\right)=\frac{16}{9}-\frac{1}{9}\left(16\right)$

$\mathrm{Convert}\:y\:\mathrm{to\:square\:form}$
$-\frac{1}{9}\left(x-4\right)^2+\frac{1}{4}\left(y^2+4y+4\right)=\frac{16}{9}-\frac{1}{9}\left(16\right)+\frac{1}{4}\left(4\right)$

$\mathrm{Convert\:to\:square\:form}$
$-\frac{1}{9}\left(x-4\right)^2+\frac{1}{4}\left(y+2\right)^2=\frac{16}{9}-\frac{1}{9}\left(16\right)+\frac{1}{4}\left(4\right)$

$\mathrm{Refine\:}\frac{16}{9}-\frac{1}{9}\left(16\right)+\frac{1}{4}\left(4\right) \ \textgreater \ -\frac{1}{9}\left(x-4\right)^2+\frac{1}{4}\left(y+2\right)^2=1$

$Refine\;once\;more\;-\frac{\left(x-4\right)^2}{9}+\frac{\left(y+2\right)^2}{4}=1$

For me I used
$\frac{\left(y-k\right)^2}{a^2}-\frac{\left(x-h\right)^2}{b^2}= 1$
$As\;\mathrm{it\;\:is\:the\:standard\:equation\:for\:an\:up-down\:facing\:hyperbola}$

I know yours is an equation which is why I did not go any further because this is the standard form you are looking for. I would rewrite mine to get my hyperbola standard form. However the one I have provided is the form you need where mine would be.
$\frac{\left(y-\left(-2\right)\right)^2}{2^2}-\frac{\left(x-4\right)^2}{3^2}=1$

Hope this helps!

4 0

3 years ago

Whats the solution of <br> y = x +2 <br> 2x - 5y = 2

aleksandr82 [10.1K]

Answer:

x = -4, y = -2

Step-by-step explanation:

substitute for y

2x - 5(x + 2) = 2

distribute -5

2x -5x - 10 = 2

solve

-3x - 10 = 2

add 10 on both sides

-3x = 12

divide by -3

x = -4

now substitute for x in the equation y = x + 2

y = -4 + 2

y = -2

7 0

2 years ago

∆ ABC and ∆ CDE are similar right triangles. The coordinates of all the vertices are integers.

Eva8 [605]

Answer: Not sure but try D

Step-by-step explanation:

not sure

6 0

3 years ago

Find the distance :

faltersainse [42]

1. You would do 45 × 3 = 135 miles
2. 630 ÷ 2 = 315. 630 + 315 = 945 miles
3. 54 × 11 = 594 miles

1. Time is distance ÷ speed, so 4760 ÷ 560 = 8 1/2hours
2. 27 ÷ 54 = 0.5 hours, or 30 minutes
3. 1748 ÷ 437 = 4 hours

I hope this helps!

4 0

3 years ago