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3 years ago

Find the area of this right triangle someone help me please

Mathematics

2 answers:

Aneli [31]3 years ago

8 0

Answer:

54 sq ft

Step-by-step explanation:

Area of a triangle is given by :

Area = (1/2) x base x height

in our case, if we assume the base of the right triangle to be 12 feet, then the height is 9 feet

Substituting this into our equation

Area = (1/2) x 12 x 9

Area = 54 sq ft

AveGali [126]3 years ago

5 0

The answer is 54 ft.²

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What is the area of the composite figure? (use 3.14 for pi). Explain how you arrived at your answer. Please round to the nearest

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The area of the given diagram is 29.817 square centimeters. The given diagram is combination of rectangle and semi circle.

Step-by-step explanation:

The given is,

Given diagram is combination of Rectangle and Semi circle.

Step:1

Res the attachment,

Area of given diagram = Area of A + Area of B..............(1)

Step:2

For A,

The A section in the given diagram is semi circle,

Diameter of semi circle = Total distance - ( 2+3)

( ∵ 2, 3 are top distance in the given diagram)

$= 10 - 5$

Diameter, d = 5 cm

Radius, $r = \frac{d}{2}$

$r = \frac{5}{2}$

r = 2.5 cm

Area, $A_{A} = \frac {\pi r^{2} }{2}$ ........................(2)

$A_{A} = \frac {\pi (2.5)^{2} }{2}$

$= \frac {\pi ( 6.25) }{2}$

$= \frac{19.63}{2}$

$A_{A} = 9.8174 cm^{2}$

Step:3

For B,

Area of rectangle is,

$A_{B} =lb$ .....................(3)

Where, l - Length = 10 cm

b - Width = 2 cm

Equation (3) become,

$= (10)(2)$

$= 20$

Area of B, $A_{B}$ = 20 $cm^{2}$

Step:4

From the equation (1),

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Area = 29.817 square centimeters

Result:

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3 years ago

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3 years ago

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The value of r so the line that passes through (-5,2) and (3,r) has a slope of -1/2 is -2

<u>Solution:</u>

Given that line is passing through point (-5, 2) and (3, r)

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Slope of a line passing through point $\left(x_{1}, y_{1}\right) \text { and }\left(x_{2}, y_{2}\right)$ is given by following formula:

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On substituting the given value in (1) we get

$\begin{array}{l}{-\frac{1}{2}=\frac{r-2}{3-(-5)}} \\\\ {\text { Solving the above expression to get value of } r} \\\\ {=>-\frac{1}{2}=\frac{r-2}{3+5}} \\\\ {=>-8=\frac{r-2}{3+5}} \\\\ {=>-8=2(r-2)} \\\\ {=>-8=2 r-4} \\\\ {=>2 r=-8+4} \\\\ {=>2 r=-4} \\\\ {=>r=\frac{-4}{2}=-2}\end{array}$

Hence the value of "r" is -2

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3 years ago