What is the answer to x/6+5-3=-2-4

In studies that use more than one data collector, how is the consistency of the data evaluated?.

Natali5045456 [20]

In order to evaluate consistency in studies with more than one data collector, the Inter-rater reliability is used.

<h3>What is the Inter-rater reliability?</h3>

This is a measure in research that is used to test the data presented by different data collectors, for consistency.

It essentially checks the extent to which the data collected from the different sources agree with each other.

Find out more on Inter-rater reliability at brainly.com/question/24711327.

#SPJ1

7 0

2 years ago

In a manufacturing plant that produces new computers, a 0.15 probability exists that a computer will be defective. if five compu

Sindrei [870]

The probability that all of them will be defective is 0.0000759375

Explanation

The general Binomial Probability formula is....

$P= ^nC_{r}*p^r*(1-p)^n^-^r$ , where p is the probability of success, n is the total number of trials and r is the desired numbers of trials.

Given, the probability that a computer will be defective is 0.15 , so p = 0.15

Five computers are manufactured and we need to find the probability that all of them will be defective. That means, n = 5 and r = 5

Now according to the above formula....

$P= ^5C_{5}*(0.15)^5*(1-0.15)^5^-^5 \\ \\ P= 1*(0.15)^5* (0.85)^0\\ \\ P=(0.15)^5 =0.0000759375$

So, the probability that all of them will be defective is 0.0000759375

7 0

3 years ago

You have two lines. Line A measures 12/16, and line B measures 3/4.

hram777 [196]

Answer:

B

Step-by-step explanation:

Let's compare the two values of 12/16 and 3/4.

Notice that 12/16 isn't a simplified fraction; both the numerator and denominator are divisible by 4. So divide the top and bottom by 4:

12 / 4 = 3

16 / 4 = 4

We are left with:

12/16 = 3/4

Now, we see that Line A and Line B are equal in length, so the answer is B.

~ an aesthetics lover

8 0

3 years ago

Read 2 more answers

Which of the following is an arithmetic sequence?

zimovet [89]

$-8~~,~~\stackrel{-8+2}{-6}~~,~~\stackrel{-6+2}{-4}~~,~~\stackrel{-4+2}{-2}\qquad \begin{cases} a_1=-8\\ d = +2 \end{cases}$

6 0

2 years ago

In college basketball, a shot made from beyond a designated arc radiating about 20 ft from the basket is worth three points ins

denis-greek [22]

Answer:

a) By the Central Limit Theorem, the distribution would be approximately normal, with mean $\mu = 0.45$ and standard deviation $s = \sqrt{\frac{p(1-p)}{n}} = \sqrt{\frac{0.45*0.55}{100}} = 0.0497$

b) 4.02 standard deviations below the mean.

c) Making 25 or less shots has a pvalue of -4.02. Z-scores lower than -2 are considered surprising, so yes, it would be surprising for him to make only 25 of these shots.

Step-by-step explanation:

To solve this question, we are going to need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For proportions, we have that the mean is $\mu = p$ and the standard deviation is $s = \sqrt{\frac{p(1-p)}{n}}$

In this problem, we have that:

$p = 0.45, n = 100$

a)By the Central Limit Theorem, the distribution would be approximately normal, with mean $\mu = 0.45$ and standard deviation $s = \sqrt{\frac{p(1-p)}{n}} = \sqrt{\frac{0.45*0.55}{100}} = 0.0497$

b)This is Z when X = 0.25.

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$

$Z = \frac{0.25 – 0.45}{0.0497}$

$Z = -4.02$

4.02 standard deviations below the mean.

c) Making 25 or less shots has a pvalue of -4.02. Z-scores lower than -2 are considered

surprising, so yes, it would be surprising for him to make only 25 of these shots.

3 0

3 years ago