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Zepler [3.9K]
3 years ago
14

Help im doing a math test

Mathematics
1 answer:
mixer [17]3 years ago
5 0

Answer:

Same doing a quiz too bro

Step-by-step explanation:

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Kiesha spent 120 minutes completing her homework last night. of those minutes, 1/6 were spent on spanish. how many minutes did k
Maslowich
Your Answer Is...

20 minutes.

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3 years ago
What is the precent of increase from 5 to 6?
Law Incorporation [45]

Answer:

20

Step-by-step explanation:

7 0
3 years ago
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Find the center, vertices, and foci of the ellipse with equation 2x2 + 8y2 = 16.
Pavlova-9 [17]

{2}x^{2}  + 8 {y}^{2}  = 16 \\  \\ 1. \:  {2x}^{2}  =  - 8 {y}^{2}  + 16 \\ 2. \:  {x}^{2}  =  - 4y^{2}  + 8 \\ 3. \: x =  \sqrt{ - 4y^{2}  + 8}  \\ x =  -  \sqrt{ - 4y^{2} + 8 }  \\  \\ answer \\ x =  \sqrt{ - 4y^{2} + 8 }  \\ x =  -  \sqrt{ - 4y^{2}  + 8}

4 0
4 years ago
Use the Chain Rule to find the indicated partial derivatives. z = x^4 + xy^3, x = uv^4 + w^3, y = u + ve^w Find : ∂z/∂u , ∂z/∂v
k0ka [10]

I'll use subscript notation for brevity, i.e. \frac{\partial f}{\partial x}=f_x.

By the chain rule,

z_u=z_xx_u+z_yy_u

z_v=z_xx_v+z_yy_v

z_w=z_xx_w+z_yy_w

We have

z=x^4+xy^3\implies\begin{cases}z_x=4x^3+y^3\\z_y=3xy^2\end{cases}

and

\begin{cases}x=uv^4+w^3\\y=u+ve^w\end{cases}\implies\begin{cases}x_u=v^4\\x_v=4uv^3\\x_w=3w^2\\y_u=1\\y_v=e^w\\y_w=ve^w\end{cases}

When u=1,v=1,w=0, we have

\begin{cases}x(1,1,0)=1\\y(1,1,0)=2\end{cases}\implies\begin{cases}z_x(1,2)=12\\z_y(1,2)=12\end{cases}

and the partial derivatives take on values of

\begin{cases}x_u(1,1,0)=1\\x_v(1,1,0)=4\\x_w(1,1,0)=0\\y_u(1,1,0)=1\\y_v(1,1,0)=1\\y_w(1,1,0)=1\end{cases}

So we end up with

\boxed{\begin{cases}z_u(1,1,0)=24\\z_v(1,1,0)=60\\z_w(1,1,0)=12\end{cases}}

3 0
3 years ago
If 4x-1=X, Find 30x<br> a) 10 b) 40<br> C) 12 d)11<br><br> How do you solve this?
cestrela7 [59]

Answer:

(a)

Step-by-step explanation:

Given

4x - 1 = x ( subtract x from both sides )

3x - 1 = 0 ( add 1 to both sides )

3x = 1 ( multiply both sides by 10 )

30x = 10 → (a)

3 0
3 years ago
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