Answer:
Bb can be an example
Explanation:
That is Because brown is dominated, so it is in Capital.
Answer:
Approximately
assuming no heat exchange between the mixture and the surroundings.
Explanation:
Consider an object of specific heat capacity
and mass
. Increasing the temperature of this object by
would require
.
Look up the specific heat of water:
.
It is given that the mass of the water in this mixture is
.
Temperature change of the water:
.
Thus, the water in this mixture would have absorbed :
.
Thus, the energy that water absorbed was:
.
Assuming that there was no heat exchange between the mixture and its surroundings. The energy that the water in this mixture absorbed,
, would be the opposite of the energy that the metal in this mixture released.
Thus:
(negative because the metal in this mixture released energy rather than absorbing energy.)
Mass of the metal in this mixture:
.
Temperature change of the metal in this mixture:
.
Rearrange the equation
to obtain an expression for the specific heat capacity:
. The (average) specific heat capacity of the metal pieces in this mixture would be:
.
Answer:
a. +10.9μC
b. 0.600N and downward
Explanation:
To determine the magnitude of the charge, we use the force rule that exist between two charges which us expressed as
F=(kq₁q₂)/r²
since q₁=-0.55μC and the force it applied on the charge above it is upward,we can conclude that the second charge is +ve, hence we calculate its magnitude as
q₂=Fr²/kq₁
q₂=(0.6N*0.3²)/(9*10⁹*0.55*10⁻⁶)
q₂=0.054/4950
q₂=1.09*10⁻⁵c
q₂=10.9μC.
Hence the second charge is +10.9μC
b. From the rule of charges which state that like charges repel and unlike charges attract, we can conclude that the two above charges will attract since they are unlike charges. Hence the direction of the force will be downward into the second charge and the magnitude of the force will remain the same as 0.600N
Answer:

Explanation:
Since, as we know, the potential difference 'ΔV' is the difference of between the Potential energy per unit charge U/qo at one point 'B' to Potential energy per unit charge at other point 'A'. It so happens when a test charge 'qo' moves from point A to B, the potential difference becomes the change of potential energy of the system, i.e.
Answer:
<h3>The answer is 336 kgm/s</h3>
Explanation:
The momentum of an object can be found by using the formula
<h3>momentum = mass × velocity</h3>
From the question
mass = 4 kg
velocity = 84 m/s
We have
momentum = 4 × 84
We have the final answer as
<h3>336 kgm/s</h3>
Hope this helps you