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solong [7]
3 years ago
14

Alice and Tom dive from an overhang into the lake below. Tom simply drops straight down from the edge, but Alice takes a running

start and jumps with an initial horizontal velocity of 25 m/s. Neither person experiences any significant air resistance. Compare the time it takes each of them to reach the lake below.
Physics
1 answer:
tangare [24]3 years ago
6 0

Answer:

Since both start with the same vertical velocity from the same position with the same acceleration they will reach the lake at the same time.

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The initial speed of a body is 7.1 m/s. What is its speed after 2.23 s if it accelerates uniformly at 2.64 m/s 2 ? Answer in uni
Nana76 [90]

13.0m/s

1.2m/s

Explanation:

Given parameters:

Initial speed of the body = 7.1m/s

time taken = 2.23s

Acceleration = 2.64m/s²

Unknown:

Final speed = ?

Solution:

Acceleration is the rate of change of velocity with time.

   a = \frac{V - U}{T}

a  = acceleration

V = final speed

U = initial speed

T = time taken

  Input the variables and solve for V;

 

   2.64 = \frac{V - 7.1}{2.23}  

  V - 7.1 = 5.9                              expression 1

  V = 5.9 + 7.1 = 13.0m/s

B

Using the same parameters, the speed after a uniform deceleration of -2.64m/s², the negative sign implies deceleration;

 from expression 1;

           V - 7.1  = -5.9

           V = -5.9 + 7.1 = 1.2m/s

learn more:

Acceleration brainly.com/question/3820012

#learnwithBrainly

5 0
3 years ago
there is a fish called an archer fish that shoots drops of water at insects resting on branches above the water. If the Archer f
Mariulka [41]

Answer:

=3.5 m/s

Explanation:

y = x tanθ - 1/2 g x² / (u²cos²θ )

y = 0.25 , x = 0.5, θ = 40°

.25 = .50 tan40 - .5 x 9.8x x²/ u²cos²40

.25 = .42 - 2.0875/u²

u = 3.5 m / s.

4 0
3 years ago
When does acceleration due to gravity equal 9.8 m/s downward?
Elza [17]

Answer:

b

Explanation:

i took the quiz i think its right

7 0
2 years ago
A bond between two copper atoms would be a<br> bond? *
mihalych1998 [28]
A metallic bond would be formed
8 0
2 years ago
Read 2 more answers
El conductor de un coche de 650 kg que va a 90 km/h frena y reduce su
Ivanshal [37]
A. 90km/h = 25 m/s
W=1/2mv^2
=1/2* 650* 25^2
= 203125(J)
b. v’= 90-50= 40km/h
= 100/9 m/s
W=1/2mv^2
=1/2*650*(100/9)^2
= 40123,45679
7 0
3 years ago
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