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3 years ago

What is the momentum of a baseball with a mass of 4 kg being thrown at a velocity of 84 m/s towards the hitter

Physics

2 answers:

Setler79 [48]3 years ago

8 0

<h2><u>Given</u> :</h2>

A mass of 4 kg being thrown at a velocity of 84 m/s towards the hitter

Momentum of a baseball

<h2><u>Solution</u> :</h2>

<u>We have</u>,

Mass = 4 kg
Velocity = 84 m/s

<u>We know that</u>,

<h3>→ Momentum = Mass × Velocity</h3>

<u>Substituting the values we get</u>,

$\implies$ Momentum = 4 × 84

$\implies$ Momentum = 336 kgm/s

∴ The momentum is 336 kgm/s.

Delvig [45]3 years ago

7 0

Answer:

<h3>The answer is 336 kgm/s</h3>

Explanation:

The momentum of an object can be found by using the formula

<h3>momentum = mass × velocity</h3>

From the question

mass = 4 kg

velocity = 84 m/s

We have

momentum = 4 × 84

We have the final answer as

Hope this helps you

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Read 2 more answers

A uniform line charge of density λ lies on the x axis between x = 0 and x = L. Its total charge is 7 nC. The electric field at x

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Answer:

The electric field at x = 3L is 166.67 N/C

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$d\vec{E} = K\frac{dq}{x^{2}}$

$d\vec{E} = K\frac{\lambda }{x^{2}}dx$

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$\int_{0}^{E}d\vec{E_{2L}} = K\lambda \int_{L}^{2L}\frac{1}{x^{2}}dx$

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Similarly,

For the field in between the range 2L< x < 3L:

$\int_{0}^{E}d\vec{E} = K\lambda \int_{2L}^{3L}\frac{1}{x^{2}}dx$

$\vec{E} = K\lambda[\frac{- 1}{x}]_{2L}^{3L}] = K\frac{Q}{L}[frac{1}{6L}]$

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Then at x = 3L:

$\frac{\vec{E_{2L}}}{3} = \frac{500}{3} = 166.67 N/C$

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