You have to figure out the highest common factor of each set of values:
9a + 21 = 3(3a + 7)
21b - 49 = 7(3b - 7)
54 - 6c = 6(9 - c)
8a + 32b = 8(a + 4b)
4p + 28q + 8r = 4(p + 7q +2r)
84a - 36b -12c = 6(14a - 6b - 2c)
6p + 9q + 15r = 3(2p + 3q + 5r)
18s - 30t + 54u = 6(3s - 5t + 9u)
Hope this helps :)
To answer you get the same denominator so multiply both denominators with each other and do the same with the top so 25 will be at both bottoms and well 15/25 and 8/25. Then solve
The median ( Q2 ) divides the data set into two parts, the upper set and the lower set. The lower quartile ( Q1 ) is the median of the lower half, and the upper quartile ( Q3 ) is the median of the upper half. Example: Find Q1 , Q2 , and Q3 for the following data set, and draw a box-and-whisker plot.
Answer:
Empirical formula= COOH
Step-by-step explanation:
Molecular mass of the elements
Carbon= 12
Oxygen= 16
Hydrogen= 1
We divide the elements each with their molecular formula
Carbon= 2.4/12
Carbon= 0.2
Oxygen= 6.4/16
Oxygen= 0.4
Hydrogen= 0.2/1
Hydrogen= 0.2
Now we divide with the smallest result which is 0.2
Carbon= 0.2/0.2
Carbon = 1
Oxygen= 0.4/0.2
Oxygen= 2
Hydrogen= 0.2/0.2
Hydrogen= 1
So we have
Carbon 1, oxygen 2, hydrogen 1
Empirical formula= COOH
