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jonny [76]
3 years ago
11

A point P has coordinates (-8, -2). What are its new coordinates after reflecting point P across the x-axis?

Mathematics
1 answer:
saul85 [17]3 years ago
7 0

Answer:

(-8,2)

Step-by-step explanation:

This is because when you reflect a point across the x-axis, the x-coordinate fo the point remains the same and the y-coordinate's sign gets switched.

(x,y) --> (x,-y)

(-8,-2) --> (-8,2)

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Y=2x-1<br> y=1/2x+4<br> find the solution to the system equations
Evgesh-ka [11]

Answer:

x=10/3 y=17/3

Step-by-step explanation:

Use substitution to solve your equation. Plug in y=2x-1 into y=1/2x+4. This makes (2x-1)=1/2x+4. Simplify this to get 3/2x-1=4. Simplify it again to get 3/2x=5. No one likes fractions so multiply both sides by 2 to get 3x=10. Simplify this and get x=10/3. Plus 10/3 into one of the equations. You can pick anyone but I picked y=2x-1. Because you know x=10/3, you put y=2(10/3)-1. Simplify this and get y=20/3-1. Convert 1 into a fraction and get y=20/3-3/3. Simplify this and get y=17/3.

Therefore,

x=10/3 y=17/3

Hoped this helps you

7 0
3 years ago
Read 2 more answers
Method for converting an angle in radians to degrees
vladimir1956 [14]

Answer:

Step-by-step explanation:

To solve for degrees: (180°/π) * radians

To solve for radians: (π/180°) * degrees

3 0
3 years ago
Wisdom scores n marks in a test. a. Antonio scores 2 marks less than wisdom. Write down an expression for Antonio's mark in term
jenyasd209 [6]
Wisdom’s score = n
Antonio’s score = n-2
8 0
3 years ago
Please help me with this!!<br> Thank u
topjm [15]

Answer:

Step-by-step explanation:

Left

When a square = a linear, always expand the squared expression.

x^2 - 2x + 1 = 3x - 5                Subtract 3x from both sides

x^2 - 2x - 3x + 1 = -5

x^2 - 5x +1 = - 5                      Add 5 to both sides

x^2 - 5x + 1 + 5 = -5 + 5

x^2 - 5x + 6 = 0

This factors

(x - 2)(x - 3)

So one solution is x = 2 and the other is x = 3

Second from the Left

i = sqrt(-1)

i^2 = - 1

i^4 = (i^2)(i^2)

i^4 = - 1 * -1

i^4 = 1

16(i^4) - 8(i^2) + 4

16(1) - 8(-1) + 4

16 + 8 + 4

28

Second from the Right

This one is rather long. I'll get you the equations, you can solve for a and b. Maybe not as long as I think.

12 = 8a + b

<u>17 = 12a + b         Subtract</u>

-5 = - 4a

a = - 5/-4 = 1.25

12 = 8*1.25 + b

12 = 10 + b

b = 12 - 10

b = 2

Now they want a + b

a + b = 1.25 + 2 = 3.25

Right

One of the ways to do this is to take out the common factor. You could also expand the square and remove the brackets of (2x - 2). Both will give you the same answer. I think expansion might be easier for you to understand, but the common factor method is shorter.

(2x - 2)^2 = 4x^2 - 8x + 4

4x^2 - 8x + 4 - 2x + 2

4x^2 - 10x + 6    The problem is factoring since neither of the first two equations work.

(2x - 2)(2x - 3)     This is correct.

So the answer is D

5 0
3 years ago
If AD is the altitude of BC, what is the slope of AD?​
koban [17]

Answer:

D

Step-by-step explanation:

First, find the slope of BC :

⇒ m (BC) = -1 - 5 / -3 - 5

⇒ m (BC) = -6/-8

⇒ m (BC) = <u>3/4</u>

Now, since AD is the altitude of BC, we can say the altitude is perpendicular to BC.

Hence, the slope of a perpendicular line is equal to the negative reciprocal of the original line.

⇒ m (AD) = - (1/m(BC))

⇒ m (AD) = - (1/(3/4))

⇒ m (AD) = -4/3

4 0
2 years ago
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