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alexdok [17]
3 years ago
10

Please answer this correctly

Mathematics
1 answer:
Alex Ar [27]3 years ago
5 0

Answer:

Area of the figure = 254.5 cm²

Step-by-step explanation:

<u><em>Area of rectangle = Length × Width</em></u>

<u><em>Area of triangle = 1/2(base × Height)</em></u>

<em>Dividing the figure into parts for convenience</em>

So,

Rectangle 1  (the uppermost):

4 × 6 = 24 cm²

Rectangle 2 (below rectangle 1):

15 × 8 = 120 cm²

Rectangle 3 (with rectangle 2):

11 × 4 = 44 cm²

Triangle 1 :

1/2(7 × 19) = 133/2 = 66.5 cm²

<em>Now adding up all to get the area of the figure:</em>

Area of the figure = 24 + 120 + 44 + 66.5

Area of the figure = 254.5 cm²

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Kay [80]

Answer:

\frac{(82)(2.4)^2}{104.139} \leq \sigma^2 \leq \frac{(82)(2.4)^2}{62.132}

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Now we just take square root on both sides of the interval and we got:

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Step-by-step explanation:

Information provided

\bar X=32.1 represent the sample mean

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Confidence interval

The confidence interval for the population variance is given by the following formula:

\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}

The degrees of freedom are given by:

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The Confidence is given by 0.90 or 90%, the value of \alpha=0.1 and \alpha/2 =0.05, the critical values for this case are:

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\chi^2_{1- \alpha/2}=104.139

And replacing into the formula for the interval we got:

\frac{(82)(2.4)^2}{104.139} \leq \sigma^2 \leq \frac{(82)(2.4)^2}{62.132}

4.535 \leq \sigma^2 \leq 7.602

Now we just take square root on both sides of the interval and we got:

2.2 \leq \sigma \leq 2.8

And the best option would be:

A.  2.2 < σ < 2.8

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