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densk [106]
3 years ago
11

20 POINTS!!HELP PLEASE!!! PICTURE IS PROVIDED!!QUESTION 6

Mathematics
1 answer:
creativ13 [48]3 years ago
6 0

Question 6

first multiply the numerator and

denominator by 9+(2)^1/2

Question 7

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Find the value of x round to the nearest tenth, i'm good with all other trigonometry lol
liraira [26]

Answer:

8.4 cm

Step-by-step explanation:

The sides involved are opposite and adjacent to the given angle. Therefore, you should use the tangent ratio.

Substitute:

tanx = opp/adj

tan35 = x/12

Multiply by 12 on both sides:

12(tan35) = (x/12)12

12(tan35) = x

Solve:

12(tan35) = x

8.4 = x

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3 years ago
Round 6.09933418366 to 4 decimal places
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3 years ago
Evalute the experssion -280+12x=
Alina [70]
The answer is 23 1/3. First, you need to add 280 to both sides of the equations in order cancel out 280 and get 12x by itself. But remember whatever you do to one side of an equation, you must to do the other. So now you have 12x=280. Now divide both sides of the equation by 12 in order to get x completely isolated. 280 divided by twelve is 23 1/3.

4 0
3 years ago
Given: △ABC, AB=5sqrt2 <br> m∠A=45°, m∠C=30°<br> Find: BC and AC
Marysya12 [62]

BC is 10 units and AC is 5+5\sqrt{3} units

Step-by-step explanation:

Let us revise the sine rule

In ΔABC:

  • \frac{AB}{sin(C)}=\frac{BC}{sin(A)}=\frac{AC}{sin(B)}
  • AB is opposite to ∠C
  • BC is opposite to ∠A
  • AC is opposite to ∠B

Let us use this rule to solve the problem

In ΔABC:

∵ m∠A = 45°

∵ m∠C = 30°

- The sum of measures of the interior angles of a triangle is 180°

∵ m∠A + m∠B + m∠C = 180

∴ 45 + m∠B + 30 = 180

- Add the like terms

∴ m∠B + 75 = 180

- Subtract 75 from both sides

∴ m∠B = 105°

∵ \frac{AB}{sin(C)}=\frac{BC}{sin(A)}

∵ AB = 5\sqrt{2}

- Substitute AB and the 3 angles in the rule above

∴ \frac{5\sqrt{2}}{sin(30)}=\frac{BC}{sin(45)}

- By using cross multiplication

∴ (BC) × sin(30) = 5\sqrt{2} × sin(45)

∵ sin(30) = 0.5 and sin(45) = \frac{1}{\sqrt{2}}

∴ 0.5 (BC) = 5

- Divide both sides by 0.5

∴ BC = 10 units

∵ \frac{AB}{sin(C)}=\frac{AC}{sin(B)}

- Substitute AB and the 3 angles in the rule above

∴ \frac{5\sqrt{2}}{sin(30)}=\frac{AC}{sin(105)}

- By using cross multiplication

∴ (AC) × sin(30) = 5\sqrt{2} × sin(105)

∵ sin(105) = \frac{\sqrt{6}+\sqrt{2}}{4}

∴ 0.5 (AC) = \frac{5+5\sqrt{3}}{2}

- Divide both sides by 0.5

∴ AC = 5+5\sqrt{3} units

BC is 10 units and AC is 5+5\sqrt{3} units

Learn more:

You can learn more about the sine rule in brainly.com/question/12985572

#LearnwithBrainly

6 0
4 years ago
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