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3 years ago

Given a set of data, what steps would you take to

Mathematics

2 answers:

lukranit [14]3 years ago

6 0

Personally, i would identify if the data shows a straight line or has a curve near the end.

Aleksandr [31]3 years ago

6 0

Make sure that the x-values are spaced apart in equal intervals.

Determine whether the y-values increase by the same amount or by the same ratio.

Decide that the data is linear because the y-values increase by a common difference.

Decide that the data is exponential because the y-values increase by a ratio or factor.

I was right on EDGE 2020

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Solve for y: x/y+9=n

Darina [25.2K]

Move all terms to the left side and set equal to zero. Then set each factor equal to zero.

y=-x9-n

Mark me as Brainleist please

8 0

3 years ago

AYUDAAAAAAA!!!!!

krok68 [10]

Answer:

Forma exacta:

x= −37/30

Forma decimal:

x=−1.23

Forma numérica mixta:

x=−17/30

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3 years ago

Find the volume of the following cylinder. 10cm h=11cm

marusya05 [52]

U didn’t give us enough info. We need the radius and then we can find the volume

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3 years ago

A trader had 30,500 eggs . He sold 12,680 of them to John and 16,570 to Peter. How many eggs he had left

zlopas [31]

Answer:

C. 17,820

Step-by-step explanation:

30,500-12,680= 17,820

4 0

2 years ago

How many ways can a person select 3 coins from a box consisting of a penny, a nickel, a dime, a quarter, a half dollar, and a on

tekilochka [14]

Answer:

A person can select 3 coins from a box containing 6 different coins in 120 different ways.

Step-by-step explanation:

Total choices = n = 6

no. of selections to be made = r = 3

The order of selection of coins matter so we will use permutation here.

Using the formula of Permutation:

nPr = $\frac{n!}{(n-r)!}$

We can find all possible ways arranging 'r' number of objects from a given 'n' number of choices.

Order of coin is important means that if we select 3 coins in these two orders:

--> nickel - dime - quarter

--> dime - quarter - nickel

They will count as two different cases.

Calculating the no. of ways 3 coins can be selected from 6 coins.

nPr = $\frac{n!}{(n-r)!}$ = $\frac{6!}{(6-3)!}$

nPr = 120

6 0

3 years ago