Which inequalities are true? Check all that apply. 0<8 8<3 8>7 8<2 8>8 1<8

Determine if the following triangles are congruent by SSS or SAS.

Sergeu [11.5K]

Answer:

They are congruent by SAS (Side Angle SIde) test or congruence criterion

Since,

In triangle ABD and triangle BCD

AB = BC (Given)

BD = DB(Common Side)

Angle ABD = Angle CBD

Therefore triangle ABD and triangle BCD by SAS (Side Angle SIde) test or congruence criterion

6 0

3 years ago

1. Pia printed two maps of a walking trail. The length of the trail on the first map is 8 cm. The length of the trail on the sec

Alex

Answer:

Step-by-step explanation:

b) 1- scale factor from the first map to the second map:

$\frac{8}{6}$ = 1.33

2- landmark on the first map is a triangle with side lengths of 3 mm, 4 mm, and 5 mm.

Side lengths of the landmark on the second map

Divide the length by scale factor:

side lengths of 3 mm: $\frac{3}{1.33}$ = 2.25 mm

side lengths of 4 mm: $\frac{4}{1.33}$ = 3.007 mm

side lengths of 5 mm: $\frac{5}{1.33}$ = 3.75 mm

5 0

3 years ago

Test scores of the student in a school are normally distributed mean 85 standard deviation 3 points. What's the probability that

Mrrafil [7]

Answer:

The probability that a random selected student score is greater than 76 is $\\ P(x>76) = 0.99865$ .

Step-by-step explanation:

The Normally distributed data are described by the normal distribution. This distribution is determined by two parameters, the population mean $\\ \mu$ and the population standard deviation $\\ \sigma$ .

To determine probabilities for the normal distribution, we can use the standard normal distribution, whose parameters' values are $\\ \mu = 0$ and $\\ \sigma = 1$ . However, we need to "transform" the raw score, in this case x = 76, to a z-score. To achieve this we use the next formula:

$\\ z = \frac{x - \mu}{\sigma}$ [1]

And for the latter, we have all the required information to obtain z. With this, we obtain a value that represent the distance from the population mean in standard deviations units.

<h3>The probability that a randomly selected student score is greater than 76</h3>

To obtain this probability, we can proceed as follows:

First: obtain the z-score for the raw score x = 76.

We know that:

$\\ \mu = 85$

$\\ \sigma = 3$

$\\ x = 76$

From equation [1], we have:

$\\ z = \frac{76 - 85}{3}$

Then

$\\ z = \frac{-9}{3}$

$\\ z = -3$

Second: Interpretation of the previous result.

In this case, the value is three (3) standard deviations below the population mean. In other words, the standard value for x = 76 is z = -3. So, we need to find P(x>76) or P(x>-3).

With this value of $\\ z = -3$ , we can obtain this probability consulting the cumulative standard normal distribution, available in any Statistics book or on the internet.

Third: Determination of the probability P(x>76) or P(x>-3).

Most of the time, the values for the cumulative standard normal distribution are for positive values of z. Fortunately, since the normal distributions are symmetrical, we can find the probability of a negative z having into account that (for this case):

$\\ P(z>-3) = 1 - P(z>3) = P(z$

Then

Consulting a cumulative standard normal table, we have that the cumulative probability for a value below than three (3) standard deviations is:

$\\ P(z$

Thus, "the probability that a random selected student score is greater than 76" for this case (that is, $\\ \mu = 85$ and $\\ \sigma = 3$ ) is $\\ P(x>76) = P(z>-3) = P(z$ .

As a conclusion, more than 99.865% of the values of this distribution are above (greater than) x = 76.

We can see below a graph showing this probability.

As a complement note, we can also say that:

$\\ P(z3)$

Which is the case for the probability below z = -3 [P(z<-3)], a very low probability (and a very small area at the left of the distribution).

5 0

3 years ago

G(x)=− 4 x 2 +7g, left parenthesis, x, right parenthesis, equals, minus, start fraction, x, start superscript, 2, end superscr

steposvetlana [31]

For this case, what we should do is evaluate the function for different points within the range shown.
We then have the following table:
x g(x)
-2 -9
-1 3
0 7
1 3
2 -9
3 -29
4 -57
From where we observed that the average rate of change is:
-13
Answer:
the average rate of change of g over the interval [-2,4] is:
-13

4 0

4 years ago

A mixture of paint calls for 1/3 of a cup of red paint and 2/3 cups of yellow paint. How many cups of red paint would be needed

garik1379 [7]

Answer:

Step-by-step explanation:

3 0

3 years ago