PH is simply a convenient way to denote hydronium ion concentration (usually in moles per liter or molarity). pH is calculated from the given concentration using the equation: pH = -log [H3O⁺]
To find [H3O+] from the given equation, we apply the antilog.
[H3O⁺] = 10⁻⁽pH⁾ or ten raised to the negative value of pH
A solution with a pH of 3.43 has a hydrogen ion concentration of 3.7154x10^-4 moles per liter.
Explanation:
Different atoms binds their outermost shell electrons with different amount of energy.
The amount of energy required to remove an electron from an atom is the ionization energy.
- Ionization energy measures the readiness of an atom to lose electrons.
- From the given problem, we can infer that in group O the ionization energy decreases down the group.
- Helium has the highest ionization energy.
- Down a group on the periodic table, ionization energy decrease because:
- atomic radii increases down the group.
- there is an increasing shielding/screening effect of inner shell electrons on the outermost shell electrons.
Learn more:
Ionization energy brainly.com/question/2153804
#learnwithBrainly
<h3>
<u>Answer:</u></h3>
<u>1 mole of a gas at STP occupies 22.4 L volume </u>
<u>Now the volume is given =78.4 therefore,</u>
<u>No. of moles of gas = 78.4 ÷ 22.4 = 3.5 moles</u>
<u>I hope it helps you~</u>
The element 238 has 238 neutrons and the element 92 has 92 neutrons.
<h3>
Answer:</h3>
5.00 mol O₂
<h3>
General Formulas and Concepts:</h3>
<u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Chemistry</u>
<u>Atomic Structure</u>
- Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.<u>
</u>
<u>Stoichiometry</u>
- Using Dimensional Analysis
<h3>
Explanation:</h3>
<u>Step 1: Define</u>
3.01 × 10²⁴ atoms O₂
<u>Step 2: Identify Conversions</u>
Avogadro's Number
<u>Step 3: Convert</u>
- Set up:

- Multiply/Divide:

<u>Step 4: Check</u>
<em>Follow sig fig rules and round. We are given 3 sig figs.</em>
4.99834 mol O₂ ≈ 5.00 mol O₂