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2 years ago

How many moles of Ar gas are present in a container with a volume of 78.4 L at STP?

Chemistry

1 answer:

rusak2 [61]2 years ago

7 0

<h3>Answer:</h3>

1 mole of a gas at STP occupies 22.4 L volume 

Now the volume is given =78.4 therefore,

No. of moles of gas = 78.4 ÷ 22.4 = 3.5 moles

I hope it helps you~

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Answer:

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General Formulas and Concepts:

Atomic Structure

Reading a Periodic Table
Moles
STP (Standard Conditions for Temperature and Pressure) = 22.4 L per mole at 1 atm, 273 K

Aqueous Solutions

States of Matter

Stoichiometry

Using Dimensional Analysis

Explanation:

Step 1: Define

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[Solve] L Ar

Step 2: Identify Conversions

[PT] Molar Mass of Ar - 39.95 g/mol

[STP] 22.4 L = 1 mol

Step 3: Convert

[DA] Set up: $\displaystyle 40.0 \ g \ Ar(\frac{1 \ mol \ Ar}{39.95 \ g \ Ar})(\frac{22.4 \ L \ Ar}{1 \ mol \ Ar})$
[DA] Divide/Multiply [Cancel out units]: $\displaystyle 24.9235 \ L \ Ar$

Step 4: Check

Follow sig fig rules and round. We are given 3 sig figs.

24.9235 L Ar ≈ 24.9 L Ar

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