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diamong [38]
3 years ago
7

If you were to spin a spinner at right what would be the probability of landing on green or purple

Mathematics
1 answer:
AURORKA [14]3 years ago
5 0

depending on how many green and purple there are, lets say 4, and there are 10 other colors, it would be 4/10 so its 40%

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A bottle of hot sauce is 3/4 full. Leigh uses 2/9 of the contents of the hot sauce bottle for lunch. How much of a full bottle o
Ymorist [56]

Answer:

Your answer will be 19/36

5 0
3 years ago
Read 2 more answers
The scale for a map is 20 miles = 1/2 inch. The distance between two towns on the map is 3 3/4 inches. What is the actual distan
zubka84 [21]

Answer:

150 miles

Step-by-step explanation:

If 1/2 of an inch is 20 miles, we can assume that 1/4 of an inch is 10 miles, since half of 1/2 is 1/4 and 1/2 of 20 is 10.

Equipped with this information, we can divide 3 by 1/2 or multiply 3 by the reciprical, 2/1 to get how much we should multiply 20 by.

3*2=6

20*6=120

Then we can multiply 10 by 3 and add that on our answer, since there are still 3/4s left and 1/4=10 miles.

10*3=30

120+30=150

The actual distance is 150 miles.

Hope this helps!

4 0
3 years ago
Write an explicit and a recursive formula for the sequence.<br> (5,11,17,23,29)
HACTEHA [7]
Starts with 5 then adds 6 repeatedly
7 0
3 years ago
n a 12 ounce bag of trail mix you notice that there are 18 M&amp;Ms. You now purchase a 20 ounce bag of trail mix. How many M&am
Maslowich

30 M&Ms

1) Gathering the data

12-ounce bag of trail mix = 18 M&Ms

20-ounce bag=?

2) Assuming that the M&Ms are placed in following a constant rate we can write the following proportion:

12 --------------- 18

20 --------------- y

<em>Cross multiplying it due to the first property of proportions</em>

<em />

12y =20 x 18

12y = 360

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3) So, I'd expect to find 30 M&Ms at a 20-ounce bag of trail mix.

6 0
1 year ago
Let E = {(x, y) e R2|xy &gt; 0}. Determine whether E is a subspace of R2 . X3
gayaneshka [121]

Answer:

E is not a subspace of \mathbb{R}^2

Step-by-step explanation:

E is not a subspace of  \mathbb{R}^2

In order to see this, we must find two points (a,b), (c,d) in  E such that (a,b) + (c,d) is not in E.

Consider

(a,b) = (1,1)

(c,d) = (-1,-1)

It is easy to see that both (a,b) and (c,d) are in E since 1*1>0 and (1-)*(-1)>0.  

But (a,b) + (c,d) = (1-1, 1-1) = (0,0)

and (0,0) is not in E.

By the way, it can be proved that in any vector space all sub spaces must have the vector zero.

5 0
3 years ago
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