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KengaRu [80]
3 years ago
15

.

Mathematics
2 answers:
alexdok [17]3 years ago
8 0

Answer: Mean = 9.3

Median = 10

Mode = 13

Step-by-step explanation:

The given data : 15, 13, 9, 9, 7, 1, 11, 10, 13, 1, 13

First arrange then in ascending order.

1, 1, 7, 9, 9, 10, 11, 13, 13, 13, 15

Now, \text{Mean}=\dfrac{\text{Sum}}{\text{Number of observations}}

\text{Mean}=\dfrac{102}{11}=9.727\approx9.3

Since, the number of observations = 11 .....odd number.

Therefore, Median = \dfrac{11+1}{2}=6^{th}\ term=10

Mode = Most repeated number = 13

laila [671]3 years ago
7 0
Median ; 1
mean; 9.27
mode; 9
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2x – бу = 12<br> -5x - 15 = -30
erastova [34]

Answer:

x=7 and y= 1/3

Step-by-step explanation:

we have -5x - 15 = -30 <=> x + 3 = 10

                                            x= 7

if x=7

so 2×7 - 6y = 12 <=> 14 - 12 = 6×y

                                 2 = 6y

                                 y= 2/6 = 1/3

3 0
3 years ago
Container 1 has 8 items, 3 of which are defective. Container 2 has 5 items, 2 of which are defective. If one item is drawn from
e-lub [12.9K]

Answer:

The required probability is \frac{19}{40}

Step-by-step explanation:

The probability of obtaining a defective item from container 1 is P(E_1)=\frac{3}{8}

The probability of obtaining a good item from container 1 is P(E_1)=\frac{5}{8}

The probability of obtaining a defective item from container 2 is P(E_1)=\frac{2}{5}

The probability of obtaining a good item from container 2 is P(E_1)=\frac{3}{5}

The cases of the event are

1)Defective item is drawn from container 1 and good item is drawn from container 2

2)Defective item is drawn from container 2 and good item is drawn from container 1

Thus the required probability is the sum of above 2 cases

P(Event)=\frac{3}{8}\times \frac{3}{5}+\frac{5}{8}\times \frac{2}{5}=\frac{19}{40}

4 0
3 years ago
There are 20 students in the high school glee club. They need to pick four students to serve as
gayaneshka [121]

Answer:

4845 ways

Step-by-step explanation:

To solve this problem we use the formula of combinations

nCr=\frac{n!}{r!(n-r)!}

Where n is the total number of students that can be chosen and you choose r from them.

So

n = 20\\r = 4

Note that in this case the order in which the 4 students are chosen does not matter.

Then

20C4=\frac{20!}{4!(20-4)!}

20C4=\frac{20!}{4!*16!}=4845\ ways

6 0
3 years ago
Read 2 more answers
The sum of a number and its reciprocal is 2whole number 1 over 6. Find that number​
notsponge [240]

Answer:

  2/3 or 3/2

Step-by-step explanation:

Let x represent the number. The given relation is ...

  x +1/x = 2 1/6

  x^2 +1 = (13/6)x

  6x^2 -13x +6 = 0 . . . . . subtract the right side and multiply by 6

  (6x -9)(6x -4)/6 = 0 . . . . factor

  (2x -3)(3x -2) = 0 . . . . . . simplify a bit

  x = 3/2  or  2/3 . . . . . . . . values of x that make the factors zero

The number is 2/3 or its reciprocal, 3/2.

6 0
2 years ago
Two friends are eating from a bag of 32 skittles sarah eats 1/2 of the 32 skittle and jami eats 1/4 of the skittles how many of
abruzzese [7]
Jami ate 8 skittles and Sarah ate 16 of the skittles together they ate a combined total of 24
7 0
3 years ago
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