Volume = length x width x height
Volume = 1 x 10 x 20.5
Volume = 205 m^3
For this case what you can do is factorize the <span>polynomial equation</span>, which would be left like follows
x ^ 3 + x ^ 2 + 9x + 9 = 0
(x + 1) (x ^ 2 + 9) = 0
Resolving, we have that the missing root is
x = -1
Answer
x=-1
Answer:
Option (2)
Step-by-step explanation:
Given expression is, AX + B = C



AX + B = C
AX = C - B
C - B =
= 
C - B = 
Let 
AX =
= 
Since AX = C - B

Therefore, a = 1, b = 5
(-3a - 4c) = -35
3(1) + 4c = 35
3 + 4c = 35
4c = 32
c = 8
And (-3b - 4d) = -11
3(5) + 4d = 11
4d = -4
d = -1
Therefore, Option (2). X =
will be the answer.
Answer:
a) 
b) 
Step-by-step explanation:
a) 
1. Distribute the second power (2) outside the first pair of parenthesis:

= 
2. Distribute the third power (3) outside the second pair of parenthesis:

= 
3. Combine like terms:

--------------------------------------------
b) 
1. Factor the number 6 (= 2 · 3):

2. Cancel the common factor (2):

3. Cancel out
in the numerator an denominator:

hope this helps!
First, you have to set a system of equations to determine the number of fiction and of nonfiction books.Call f the number of fiction books and n the number of nonfiction books. Then 400 = f + n. And f = n + 40 => n = f - 40 => 400 = f + f - 40 => 400 - 40 = 2f => f = 360 / 2 = 180. Now to find the probability of picking two fiction books, take into account the the Audrey will pick from 180 fiction books out of 400, and Ryan will pick from 179 fiction books out of 399, so the probability will be<span> (180/ 400) * (179/399) = 0.20 (rounded to two decimals). Answer: 0.20</span>