Three identical circular coins are lined up in a row as shown (the 10s represent their value, not a length). The distance betwee
n the first and third coins is 3.2 cm. What is the diameter of one of these coins?
1 answer:
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Answer:
perimeter of the shaded region = 88 +44+28 =160 cm
Step-by-step explanation:
perimeter of shaded region = length AO + arc OB + arc AB
length AO = radius of bigger circle
radius of bigger circle = OX + OB = 2×radius of smaller circle = 2×14 cm = 28 cm
therefore AO = 28 cm
length of arc oB= half of circumference of smaller circle = ×14 = 44 cm
length of arc ab = half of circumference of bigger circle = ×28 =
×28= 88
therefore perimeter of the shaded region = 88 +44+28 =160 cm
area of the shaded region = half of area of bigger circle - half of area of smaller circle
=
=
solving we gen area of shaded region = 924
Given
So,
So, the simplest form of 88/90 is 44/45