The absolute value is basically the distance from zero, and distance is ALWAYS positive. After you removed your negatives, you need to just compare the values. For example. The smallest absolute value between -27 and 19 is 19. Hope this helped!
P(t)=500(1+4t/(50+t^2 ))
P'(t) = 500 [(50+t^2).4 - 4t.2t]/(50+t^2)^2
by the quotient rule
500 (-4t^2 + 200)/(t^2 + 50)^2
Hence
P'(2) = 500 . (-16 + 200)/54^2 ~= 31.6
Not sure if you’re speaking Spanish or not but yes
Answer:

Step-by-step explanation:
step 1
In the right triangle ABC
Applying the Pythagoras Theorem fin the hypotenuse AC

substitute



step 2
we know that
If two figures are similar, then the ratio of its corresponding sides is equal
so

substitute and solve for CE

step 3
Find the length of segment AE
AE=AC+CE
substitute the values
