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Alchen [17]
3 years ago
5

What is the length of segment AE?

Mathematics
1 answer:
nexus9112 [7]3 years ago
6 0

Answer:

AE=\frac{50}{3}\ units

Step-by-step explanation:

step 1

In the right triangle ABC

Applying the Pythagoras Theorem fin the hypotenuse AC

AC^{2} =AB^{2}+BC^{2}

substitute

AC^{2} =6^{2}+8^{2}

AC^{2} =100

AC =10\ units

step 2

we know that

If two figures are similar, then the ratio of its corresponding sides is equal

so

\frac{AB}{CD}=\frac{AC}{CE}

substitute and solve for CE

\frac{6}{4}=\frac{10}{CE}\\ \\CE=4*10/6\\ \\CE=\frac{20}{3}\ units

step 3

Find the length of segment AE

AE=AC+CE

substitute the values

AE=10\ units+\frac{20}{3}\ units=\frac{50}{3}\ units

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Answer:

The zeros of the given polynomial function are

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Step-by-step explanation:

Given polynomial is P(x)=x^4-4x^3-x^2+20x-20

To find the zeros equate the given polynomial to zero

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By using synthetic division we can solve the polynomial:

2_|   1     -4     -1      20      -20

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   _____________________

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Therefore x-2=0

x=2 is a zero of P(x)

Now we can write the cubic equation as below:

x^3-2x^2-5x+10=0

Again using synthetic division

2_|   1     -2     -5     10      

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Therefore x-2=0

x=2 is also a zero of P(x).

Now we have x^2+0x-5=0

x^2-5=0

x^2=5

x^=\pm\sqrt{5} is a zero of P(x)

Therefore the zeros are 2,2,\pm\sqrt{5}

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