Answer:
8/15
Step-by-step explanation:
get common demonmater
15 can work!
1/3 times what = 15 ?
5 right? and then 1/5 times what = 15?
3 right?
Finally add 5+3 which is 8
SO 8/15!
Answer: ![1,179\pi\ in^3](https://tex.z-dn.net/?f=1%2C179%5Cpi%5C%20in%5E3)
Step-by-step explanation:
The volume of a cylinder can be calculated with the following formula:
![V=\pi r^2h](https://tex.z-dn.net/?f=V%3D%5Cpi%20r%5E2h)
Where "r" is the radius and "h" is the height.
The volume of a sphere can be found with this formula:
![V=\frac{4}{3}\pi r^3](https://tex.z-dn.net/?f=V%3D%5Cfrac%7B4%7D%7B3%7D%5Cpi%20%20r%5E3)
Where "r" is the radius.
Then, volume of the empty cylinder is:
![V_c=\pi (\frac{18\ in}{2})^2(15\ in)\\\\V_c=1,215\pi \ in^3](https://tex.z-dn.net/?f=V_c%3D%5Cpi%20%28%5Cfrac%7B18%5C%20in%7D%7B2%7D%29%5E2%2815%5C%20in%29%5C%5C%5C%5CV_c%3D1%2C215%5Cpi%20%5C%20in%5E3)
And the volume of the ball is:
![V_b=\frac{4}{3}\pi (\frac{6\ in}{2})^3\\\\V_b=36\pi \ in^3](https://tex.z-dn.net/?f=V_b%3D%5Cfrac%7B4%7D%7B3%7D%5Cpi%20%20%28%5Cfrac%7B6%5C%20in%7D%7B2%7D%29%5E3%5C%5C%5C%5CV_b%3D36%5Cpi%20%5C%20in%5E3)
Finally, you need to subtract them in order to calculate how much water is in the cylinder:
![1,215\pi \ in^3-36\pi \ in^3=1,179\pi\ in^3](https://tex.z-dn.net/?f=1%2C215%5Cpi%20%5C%20in%5E3-36%5Cpi%20%5C%20in%5E3%3D1%2C179%5Cpi%5C%20in%5E3)
Answer: ⇒ ![{x=1.51=1.50=2.0}](https://tex.z-dn.net/?f=%7Bx%3D1.51%3D1.50%3D2.0%7D)
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Step-by-step explanation:
First you had to subtract by 5.2 from both sides of equation.
![3.1x+5.2-5.2=9.9-5.2](https://tex.z-dn.net/?f=3.1x%2B5.2-5.2%3D9.9-5.2)
![3.1x=4.7](https://tex.z-dn.net/?f=3.1x%3D4.7)
Then you divide by 3.1 from both sides of equation.
![\frac{3.1x}{3.1}= \frac{4.7}{3.1}](https://tex.z-dn.net/?f=%5Cfrac%7B3.1x%7D%7B3.1%7D%3D%20%5Cfrac%7B4.7%7D%7B3.1%7D)
Simplify it's should be the correct answer.
![x=1.51=1.50=2.0](https://tex.z-dn.net/?f=x%3D1.51%3D1.50%3D2.0)
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Hope this helps!
Thank you for posting your question at here on brainly.
Have a great day!
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I think you could do
(5+4)×2+6-(2×2)-1