The sum of two sides of a triangle must be greater than the third side
1) 5+9>14
14>14 It is incorrect so you can’t have these lengths
2)7+7>15
14>15 X
3)1+2>4
3>4 X
4)3+6>8
9>8
6+8>3
14>3
8+3>6
11>6
So the fourth choice is correct
Answer:
(4x^2 +9)(4x^2-9) =0
Step-by-step explanation:
16x^4 - 18 = 0
Rewriting
(4x^2)^2 - 9^2 =0
We notice that this is the difference of squares
a^2 - b^2 = (a-b)(a+b)
(4x^2 -9)(4x^2+9) =0
Let the number be x.
x/3 + 12 = 46
Subtract 12 from both sides and you will get:
x/3 = 34
Multiply both sides by 3:
x = 102
