Answer:
The height of triangle is
Step-by-step explanation:
we know that
The area of a triangle is equal to
In this problem we have
substitute in the formula and solve for h
Answer:
20/5=number in each group. It can also be S/5
Step-by-step explanation:
Answer:
59.2 m
Step-by-step explanation:
The tangent of the angle of elevation will be the ratio of pole height to distance from the pole:
tan(2α) = h/10
tan(α) = h/70
The double-angle formula for tangents tells us ...
tan(2α) = 2tan(α)/(1 -tan(α)²)
Multiplying by the denominator and substituting from above, we get ...
(1 -(h/70)²)(h/10) = 2(h/70)
7(1 -(h/70)²) = 2 . . . . . . . . multiply by 70/h
1 - 2/7 = (h/70)² . . . . . . . . divide by 7, subtract 2/7-(h/70)²; next: square root
h = 70√(5/7) ≈ 59.2 . . . . meters
The height of the top of the pole is about 59.2 meters above the observer.
Answer:
The vertices of the triangle A'B'C' are , and , respectively.
Step-by-step explanation:
Vectorially speaking, the reflection of a point over the x-axis is defined by the following expression:
(1)
Where:
- Original point.
- Reflected point.
If we know that , and , then the vertices of the triangle A'B'C':
, ,
The vertices of the triangle A'B'C' are , and , respectively.
Answer:
This angle is not a right angle from what it looks like, but this angle if you turn it sideways, angle JKN should be a little more than 90 which classifies it as an obtuse angle.