Answer:
Explanation:
<u>1) Data:</u>
a) mass of solute = ?
b) volume of solution = 1.25 liter
c) M = 2.92 mol/liter
d) solute NaOH
<u>2) Formulae:</u>
<u />
a) Molarity, M = number of moles of solute / volume of solution in liters
b) mass in grams = molar mass × number of moles
<u>3) Solution:</u>
a) <u>Calculate number of moles of solute</u>:
- M = number of moles of solute / volume of solution in liters
⇒ number of moles of solute = M × volume of solution in liters
⇒ number of moles of solute = 2.92 mol/liter × 1.25 liter = 3.65 mol
b) <u>Molar mass of NaOH = 39.997 g/mol </u>(you can take this number from internet or calculate it using the atomic masses of Na, O, and H).
c) <u>Calculate the mass of solute:</u>
- mass in grams = molar mass × number of moles = 39.997 g/mol × 3.65 mol = 145.98905 g = 146. g
The answer must be reported with 3 significant figures, so it is 146. g.
Coal does not produce flame when burnt because it does not vapourizes
Explanation:
The only flaw I can find is you squared 3 instead of cubing it and it will be 27X^4 instead of 9x^4.
This reduces the amount slightly, but the number is still incredibly high (about 10 ^ 5 L is what I've calculated). Your professor might want to point out that this will not be a effective experiment due to the large volume of saturated
The Ksp value of Ca(OH)2 on the site (I used 5.5E-6 [a far more soluble compound than Al(OH)3]) and estimated how much of it will be needed. My calculation was approximately 30 ml. If you were using that much in the experiment, it implies so our estimates for Al(OH)3 are right, that the high amount is unreasonably big and that Al(OH)3 will not be a suitable replacement unless the procedure was modified slightly.
382.75 is the temperature of the 0.750 mol of an ideal gas occupy a volume of 35.9 L at 114 kPa.
Explanation:
Given:
number of moles (n) = 0.750
volume of the gas = 35.9 litres
pressure on the ideal gas = 114 kPa or 1.125 atm
R (gas constant) = 0.0821J/Kmole
Absolute temperature of gas in celcius =?
the equation for the ideal gas is
PV = nRT
putting the values in the above equation:
T =
=
= 655.907
655.9 kelvin is the temperature of the ideal gas.
To convert this unit of kelvin into degree celcius:
K-273.15 = C
655.9 - 273.15
= 382.75 degrees
382.75 degrees celcius is the temperature of the ideal gas.
Answer:
Liquid
Explanation:
My reason is that liquid takes the shape of any container and can also be expand by boiling to change it volume also be compressed by freezing or less than it room temperature
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