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Tanya [424]
2 years ago
14

Which best describes the process that occurs when liquid water becomes ice?

Chemistry
2 answers:
DerKrebs [107]2 years ago
8 0

Answer:

The water molecules get condensed and form a solid matter called ice. This process is called Condensation.

garri49 [273]2 years ago
7 0

Answer:

Freezing

Explanation:

When a liquid goes to a solid, this process is called freezing.

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Which of the following would not be an isotope of carbon-12? A. Carbon-14 B. Carbon-13 C. Boron-12 D. Carbon-11
Oliga [24]
C because it isn't carbon
6 0
3 years ago
How many hydrogen atoms are in a cycloalkane with 8 carbon atoms?
frosja888 [35]
Cycloalkanes are those saturated organic compounds which exist in the form of Rings. Their Hydrogen Deficiency Index in one. The General formula for cycloalkanes is,
                                                  CnH2n
When number of Carbons = 8
Then
                                                  C₈H₂₍₈₎

                                                  C₈H₁₆

Result:
           
Cycloalkane containing 8 carbon atoms has 16 hydrogen atoms.

8 0
3 years ago
P4O10 -> 4P+5O2 How many moles of phosphorus would be produced if 5.3 mol of P4O10 reacted?
viktelen [127]

Answer:

21.2 moles.

Explanation:

Hello!

In this case, for the given chemical reaction, we can see there is a 1:4 mole ratio between tetraphosphorous decaoxide and phosphorous; therefore, the following proportional factor provides the requested moles of phodphorous:

n_P=5.3molP_4O_{10} *\frac{4molP}{1molP_4O_{10}} \\\\n_P=21.2molP

Best regards!

5 0
3 years ago
16 meters per hour to miles per sec
ss7ja [257]

Answer:

2.76 (full answer) 2.7617e-6

Explanation:

6 0
3 years ago
A binding protein binds to a ligand l with a kd of 400 nm what is the concentration of ligand when y is 0.25
vampirchik [111]

Answer:

The answer is 7600 nm.

Explanation:

As, Y = 0.25 = [ L ÷ (400 + (L)]

0.95 x 400 + 0.25 [ L] = [ L ]

380.25  = [ L ] - 0.95 [ L ]

              = 0.05 [L]

[L] = 380 ÷ 0.05 = 7600nm

6 0
3 years ago
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