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Tanya [424]
2 years ago
14

Which best describes the process that occurs when liquid water becomes ice?

Chemistry
2 answers:
DerKrebs [107]2 years ago
8 0

Answer:

The water molecules get condensed and form a solid matter called ice. This process is called Condensation.

garri49 [273]2 years ago
7 0

Answer:

Freezing

Explanation:

When a liquid goes to a solid, this process is called freezing.

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The total number of oxygen atoms indicated by formula Cu3(PO4)2?
ASHA 777 [7]

Answer:

There's a total of 8 oxygen atoms in the formula Cu3(PO4)2

6 0
3 years ago
Su şeker karışımını ayırma yöntemi nedir arkadaşlar
Alinara [238K]
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3 0
3 years ago
PLEASE HELP!! WILL MARK BRAINLIEST AND THANK YOU!! EXTRA POINTS!!
babunello [35]

Answer:

Balance

Measures mass

Metric Ruler

Measures length

Units - centimeter

Spring Scale

Measures weight

Units - grams

Graduated Cylinder

Measures liquid volume

i think this is the right answer please don't report me

8 0
3 years ago
A) Find the gas speed of sulfur dioxide at 100.0 degrees Celsius? ______________
gtnhenbr [62]

a. 381.27 m/s

b. the rate of effusion of sulfur dioxide = 2.5 faster than nitrogen triiodide

<h3>Further explanation</h3>

Given

T = 100 + 273 = 373 K

Required

a. the gas speedi

b. The rate of effusion comparison

Solution

a.

Average velocities of gases can be expressed as root-mean-square averages. (V rms)  

\large {\boxed {\bold {v_ {rms} = \sqrt {\dfrac {3RT} {Mm}}}}

R = gas constant, T = temperature, Mm = molar mass of the gas particles  

From the question  

R = 8,314 J / mol K  

T = temperature  

Mm = molar mass, kg / mol  

Molar mass of Sulfur dioxide = 64 g/mol = 0.064 kg/mol

\tt v=\sqrt{\dfrac{3\times 8.314\times 373}{0.064} }\\\\v=381.27~m/s

b. the effusion rates of two gases = the square root of the inverse of their molar masses:  

\rm \dfrac{r_1}{r_2}=\sqrt{\dfrac{M_2}{M_1} }

M₁ = molar mass sulfur dioxide = 64

M₂ =  molar mass nitrogen triodide = 395

\tt \dfrac{r_1}{r_2}=\sqrt{\dfrac{395}{64} }=\dfrac{20}{8}=2.5

the rate of effusion of sulfur dioxide = 2.5 faster than nitrogen triodide

4 0
3 years ago
If the half-life of a radioisotope is 10,000 years, the amount remaining after 20,000 years is
Cloud [144]

Answer:

Considering the half-life of 10,000 years, after 20,000 years we will have a fourth of the remaining amount.

Explanation:

The half-time is the time a radioisotope takes to decay and lose half of its mass. Therefore, we can make the following scheme to know the amount remaining after a period of time:

Time_________________ Amount

t=0_____________________x

t=10,000 years____________x/2

t=20,000 years___________x/4

During the first 10,000 years the radioisotope lost half of its mass. After 10,000 years more (which means 2 half-lives), the remaining amount also lost half of its mass. Therefore, after 20,000 years, the we will have a fourth of the initial amount.

6 0
3 years ago
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