What is the correct empirical formula for C18H306?

when copper metal is heated it reacts with a gas in the air . what iz the name of the product formed when copper reacts with a g

Dvinal [7]

Answer:

Heated copper metal reacts with oxygen to form the black copper oxide. The copper oxide can then react with the hydrogen gas to form the copper metal and water.

5 0

3 years ago

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1.) How do plant scientists hope to improve plant processes?

NISA [10]

Question:

1.) How do plant scientists hope to improve plant processes?

Answer:

January 2, 2012. Plant scientists long have known they can alter crops genetically to improve performance; they've been doing it thousands of years.

Question:

2.) How could you find out which resources are the most important for a plant to grow?

Answer:

Three elements, carbon, oxygen and hydrogen, are essential to plant growth and are supplied by air and water.

Hope it helps (^^)

# Cary on learning

6 0

3 years ago

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How many grams are equivalent to 20 moles of water?

Eduardwww [97]

Answer: 360.3056 grams i think

Explanation:

3 0

3 years ago

The volume of a gas is 650. mL at 1.14°C. What will the volume be a 75.0°C?

tia_tia [17]

Answer: The final volume of the gas is 825.12 mL

Explanation:

To calculate the final temperature of the system, we use the equation given by Charles' Law. This law states that volume of the gas is directly proportional to the temperature of the gas at constant pressure.

Mathematically,

$\frac{V_1}{T_1}=\frac{V_2}{T_2}$

where,

$V_1\text{ and }T_1$ are the initial volume and temperature of the gas.

$V_2\text{ and }T_2$ are the final volume and temperature of the gas.

We are given:

$V_1=650mL\\T_1=1.14^oC=(1.14+273)K=274.14K\\V_2=?mL\\T_2=75^oC=(75+273)K=348K$

Putting values in above equation, we get:

$\frac{650mL}{274.14K}=\frac{V_2}{348K}\\\\V_2=\frac{650\times 348}{274.14}=825.12mL$

Hence, the final volume of the gas is 825.12 mL

3 0

3 years ago

An HCl solution has a concentration of 0.09714 M. Then 10.00 mL of this solution was then diluted to 250.00 mL in a volumetric f

cestrela7 [59]

Answer:

A. Concentration of diluted acid = 0.00389 M

B. Concentration of OH- in AgOH solution = 0.00012 M

Explanation:

A. Using the dilution formula: C1V1 = C2V2

Where C1 is the initial concentration, V1 is the initial volume, C2 is the final concentration, and V2 is the final volume.

From the data provided, C1 = 0.09714 M, V1 = 10.0 mL, V2 = 250.0 mL and C2 = ?

Making C2 subject of the formula above; C2 = C1V1/V2

C2 = 0.09714 M × 10 / 250 = 0.00389 M

B. Equation of the neutralization reaction is given below:

HCl + AgOH ---> AgCl + H₂O

From the equation, 1 mole of acid neutralizes 1 mole of base

Using the titration formula; CaVa/CbVb = na/nb

Where Ca is the concentration of the acid HCl = 0.00389 M

Va is the volume of acid = 7.93 mL

Cb is the concentration of base, AgOH = ?

Vb is volume of base = 250.0 mL

na/nb = mole ratio of acid and base = 1

Making Cb subject of the formula in the equation above; Cb = CaVa/Vb

Cb = 0.00389 M × 7.93 / 250

Cb = 0.00012 M

7 0

3 years ago