Answer:
0.0814 Wb
Explanation:
L = length of the rectangular coil = 5 cm = 0.05 m
w = width of rectangular coil = 7 cm = 0.07 m
A = Area of the coil = L w = 0.05 x 0.07 = 35 x 10⁻⁴ m²
B = magnitude of uniform magnetic field = 0.55 T
θ = angle of axis of coil with magnetic field = 65°
Magnetic flux through the coil is given as
Φ = N B A Cosθ
Φ = (100) (0.55) (35 x 10⁻⁴ ) Cos65
Φ = 0.0814 Wb
Answer:
Output voltage is 1.507 mV
Solution:
As per the question:
Nominal resistance, R = 
Fixed resistance, R =
Gauge Factor, G.F = 2.01
Supply Voltage, 
Strain, 
Now,
To calculate the output voltage, 
:
WE know that strain is given by:
Thus
Now, substituting the suitable values in the above eqn:
Answer:
no lol.. is this actually for school?
Motion is physics. motion is the displacement,distance,velocity, acceleration, time, and speed.
6.
A. 1575 - 1265 = 310J
B. KE 1/2 MV^2
V=√2·KE/M = √2(310)/12 V = 7.2mls
C. PE = 1265 = mgh
h= 1265/mg = 1265/(12)(92) h= 10.8m
7.
A. KE = 1/2 mv^2 0.5(5)(12)^2 KE = 360J
B. PE = mgh = (5)(9.8)(2.6) PE = 127.4J
C. ME = KE + PE = 360 + 127.4 ME = 487.4J
