Here's the solution ~
As we know, we can calculate the circumference of a circle in terms of its diameter as :
where, c = circumference and d = diameter
And also, circumference of circle is terms of radius (r) is :
Now, let's move on to questions ~
<h3>First </h3>
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<h3>Second</h3><h3 /><h3 /><h3 /><h3>
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<h3>Third</h3>
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<h3>Fourth</h3>
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<h3>Fifth </h3>
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<h3>Sixth</h3>
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Consider point P(x,y) such that P, X and Y are collinear,
As vectors
XP = XO + OZ where O(0,0)
XP = OZ - OX
XP= (x,y) - (-3,3)
XP = (x+3, y-3)
Similarly,
PY = (6-x, -3-y)
But XP= 2^PY
[x+3, y-3] = [2(6-x), 2(-3-y)]
Given both vectors are equal, as they go in the same direction, Solve for x and y accordingly:
x+3 = 12 - 2x
x = 3
y-3 = -6-2y
y = -1
Therefore, P(3,-1)
2 triangles make up a rhombus
The distance traveled by the second hand of the clock is 0.471 m.
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To calculate the distance the tip of the second hand of the clock travel in 45 seconds, we use the formula below.
<h3>Formula:</h3>
- L = 2πr∅/360.................. Equation 1
<h3> Where: </h3>
- L = distance traveled by the tip of the second hand.
- r = Length of the second hand
- ∅ = angle formed by the second hand of the clock
- π = pie
From the question,
<h3>Given:</h3>
- r = 10 cm = 0.1 m
- ∅ = (360×45/60) = 270°
- π = 3.14
Substitute these values into equation 1
- L = 0.1×2×270×3.14/360
- L = 0.471 cm.
Hence, The distance traveled by the second hand of the clock is 0.471 m
Learn more about distance traveled here: brainly.com/question/4931057
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