Answer:
Solving 14t-3t we get 22 and 3t-14t we get -22
So, 14t-3t is not equivalent to 3t-14t.
Step-by-step explanation:
We need to explain weather 14t-3t is equivalent to 3t-14t. Support your sender by evaluating the expression for t=2.
<em>Equivalent expressions are those that have same values for any value of variable substituted.</em>
Now, We check if our expressions are equivalent, by evaluating the expression for t=2.
If they are equivalent, they would have same result after evaluation.
First, put t=2 into 14t-3t
Now put t=2, into 3t-14t
For solving 14t-3t we get 22 and 3t-14t we get -22
So, 14t-3t is not equivalent to 3t-14t.
Answer:
I believe the correct answer is B.
Answer:
The endpoints of the latus rectum are 
and 
.
Step-by-step explanation:
A parabola with vertex at point 
and whose axis of symmetry is parallel to the y-axis is defined by the following formula:
(1)
Where:
- Independent variable.
- Dependent variable.
- Distance from vertex to the focus.
, 
- Coordinates of the vertex.
The coordinates of the focus are represented by:
(2)
The <em>latus rectum</em> is a line segment parallel to the x-axis which contains the focus. If we know that 
, 
and 
, then the latus rectum is between the following endpoints:
By (2):
By (1):
There are two solutions:
Hence, the endpoints of the latus rectum are and .
9514 1404 393
Answer:
(a) x = (3 -ln(3))/5 ≈ 0.819722457734
(b) y = 10
Step-by-step explanation:
(a) Taking the natural log of both sides, we have ...
2x +1 = ln(3) +4 -3x
5x = ln(3) +3 . . . . . . . . add 3x-1
x = (ln(3) +3)/5 ≈ 0.820
__
(b) Assuming "lg" means "log", the logarithm to base 10, we have ...
log(y -6) +log(y +15) = 2
(y -6)(y +15) = 100 . . . . . . . taking antilogs
y^2 -9x -190 = 0 . . . . . . . . eliminate parentheses, subtract 100
(y -19)(y +10) = 0 . . . . . . . . factor
The values of y that make these factors zero are -19 and 10. We know from the first term that (y-6) > 0, so y > 6. That means y = -19 is an extraneous solution.
The solution is ...
y = 10
__
When solving equations using a graphing calculator, it often works well to define a function f(x) such that the solution is f(x) = 0, the x-intercept(s). That form is easily obtained by subtracting the right side of the equation from both sides of the equation. In part (a) here, that is ...
f(x) = e^(2x+1) -3e^(4-3x)
