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Kay [80]
3 years ago
12

Helppp! Is Figure A’B’C’D’ a reflection of Figure ABCD? Explain. *

Mathematics
1 answer:
Korolek [52]3 years ago
8 0
Yes. It would be a reflection over the line.
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What is the value of the function at x = −3?
zlopas [31]

Answer:

the answer is D

Step-by-step explanation:

(0, -3) , (1, -3) , (2, -3)

Hope this helps! :)

~Zane


4 0
3 years ago
Read 2 more answers
Evaluate the following integrals: 1. Z x 4 ln x dx 2. Z arcsin y dy 3. Z e −θ cos(3θ) dθ 4. Z 1 0 x 3 √ 4 + x 2 dx 5. Z π/8 0 co
Zigmanuir [339]

Answer:

The integrals was calculated.

Step-by-step explanation:

We calculate integrals, and we get:

1) ∫ x^4 ln(x) dx=\frac{x^5 · ln(x)}{5} - \frac{x^5}{25}

2) ∫ arcsin(y) dy= y arcsin(y)+\sqrt{1-y²}

3) ∫ e^{-θ} cos(3θ) dθ = \frac{e^{-θ} ( 3sin(3θ)-cos(3θ) )}{10}

4) \int\limits^1_0 {x^3 · \sqrt{4+x^2} } \, dx = \frac{x²(x²+4)^{3/2}}{5} - \frac{8(x²+4)^{3/2}}{15} = \frac{64}{15} - \frac{5^{3/2}}{3}

5)  \int\limits^{π/8}_0 {cos^4 (2x) } \, dx =\frac{sin(8x} + 8sin(4x)+24x}{6}=

=\frac{3π+8}{64}

6)  ∫ sin^3 (x) dx = \frac{cos^3 (x)}{3} - cos x

7) ∫ sec^4 (x) tan^3 (x) dx = \frac{tan^6(x)}{6} + \frac{tan^4(x)}{4}

8)  ∫ tan^5 (x) sec(x)  dx = \frac{sec^5 (x)}{5} -\frac{2sec^3 (x)}{3}+ sec x

6 0
3 years ago
What is 0.75% of 387
luda_lava [24]

Answer: 2.9025


Step-by-step explanation:

0.75 x 387/100  

= 2.9025

3 0
3 years ago
Read 2 more answers
Select the statement that describes this expression: 5 x 3 − (2 x 4) + 5. (2 points)
Nana76 [90]

Answer:

I believe the answer is either going to be B or C

Step-by-step explanation:

7 0
3 years ago
The 7th grade has 159 students. There are twice as many boys in the grade as there are girls.
aleksklad [387]

Answer:

106 boys

Step-by-step explanation:

7th grade = 159 students

Boys to girls ratio:

2:1

Find two thirds of 159:

2/3*159 = 106 boys

159-106= 53 girls

Check:

53*2 = 106

3 0
3 years ago
Read 2 more answers
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