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2 years ago

It's like ratio on big ideas math 2.1 Exercises BigIdesMath.com

Mathematics

1 answer:

ryzh [129]2 years ago

4 0

Answer:

what? I don't understand explain

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331 students went on a field trip. Six buses were filled and 7 student traveled in cars. How many students were in buses.

lilavasa [31]

Yes because you subtract seven from 331 and that gives you 324 and you divide 324 divided by 6 and that gives you 54

3 0

2 years ago

Spencer is asked to factor the polynomial 256x^4y^2−y^2 completely over the integers. His work is shown below.

mr Goodwill [35]

Answer:

Option B, Spencer did not factor the polynomial completely; 16x^2−1 can be factored over the integers.

Step-by-step explanation:

Step 1: Factor

256x^4y^2−y^2

y^2(256x^4 - 1)

y^2(16x^2 - 1)(16x^2 + 1)

y^2(4x + 1)(4x - 1)(16x^2 + 1)

Answer: Option B, Spencer did not factor the polynomial completely; 16x^2−1 can be factored over the integers.

7 0

3 years ago

Read 2 more answers

ACDF is a trapezoid and

Sholpan [36]

Answer:

x = 7

Step-by-step explanation:

See the attached figure.

As shown: A C D F is a trapezoid and BE is a mid-segment.

The mid-segment of the trapezoid is the average of its bases.

BE = 0.5 ( A F + C D)

Given: CD = 18 , BE = 2x + 10 and A F = 6x - 12

So,

2x + 10 = 0.5 ( 18 + 6x - 12)

Solve for x

2x + 10 = 0.5 (6 + 6x)

2x + 10 = 3 + 3x

10 - 3 = 3x - 2x

∴ x = 7

So, the value of x is 7

8 0

2 years ago

6) Two coastguard stations P and Q are 17km apart, with due East of P. A ship S is observed in distress on a bearing 048° fromP

adelina 88 [10]

Answer:

The ship S is at 10.05 km to coastguard P, and 12.70 km to coastguard Q.

Step-by-step explanation:

Let the distance of the ship to coastguard P be represented by x, and its distance to coastguard Q be represented by y.

But,

<P = 048°

<Q = $360^{o}$ - $324^{o}$

= 0 $36^{o}$

Sum of angles in a triangle = $180^{o}$

<P + <Q + <S = $180^{o}$

048° + 0 $36^{o}$ + <S = $180^{o}$

$84^{o}$ + <S = $180^{o}$

<S = $180^{o}$ - $84^{o}$

= $96^{o}$

<S = $96^{o}$

Applying the Sine rule,

$\frac{y}{Sin P}$ = $\frac{x}{Sin Q}$ = $\frac{z}{Sin S}$

$\frac{y}{Sin P}$ = $\frac{z}{Sin S}$

$\frac{y}{Sin 48^{o} }$ = $\frac{17}{Sin 96^{o} }$

$\frac{y}{0.74314}$ = $\frac{17}{0.99452}$

⇒ y = $\frac{12.63338}{0.99452}$

= 12.703

y = 12.70 km

$\frac{x}{Sin Q}$ = $\frac{z}{Sin S}$

$\frac{x}{Sin 36^{o} }$ = $\frac{17}{Sin 96^{o} }$

$\frac{x}{0.58779}$ = $\frac{17}{0.99452}$

⇒ x = $\frac{9.992430}{0.99452}$

= 10.0475

x = 10.05 km

Thus,

the ship S is at a distance of 10.05 km to coastguard P, and 12.70 km to coastguard Q.

6 0

3 years ago

What are two consecutive numbers whose cubes differ by 331

Vinvika [58]

Jsnsjsjjsjsjsjsjsjsjsjsj hsjsjsjsj

5 0

3 years ago