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Schach [20]
2 years ago
11

Find the domain of f(x)= x/x-9

Mathematics
1 answer:
sveta [45]2 years ago
3 0

Answer:

Step-by-step explanation:

The domain, the possible values of x, is only limited in this function when the function is undefined. Specifically division by zero is undefined. In this case x cannot be equal to 9 because that would lead to division by zero. And that is the only restriction. So the domain is all real numbers except 9. In interval notation this is

x=(-oo, 9),(9, +oo)

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Trever Goetz is a salesperson who is paid a monthly salary of $500 plus a 2% commission on sales. How much must he sell to earn
dedylja [7]
Whatever% of anything is just (whatever/100) * anything.

now, we know Trever makes $500 in salary and 2% on sales, let's say he sells "x" amount, how much is 2% of x?  well (2/100) * x, or 0.02x.

Therefore Trever's earnings are 500 + 0.02x, his salary plus his commission.

to earn a total of 2,000, then 500 + 0.02x = 2000, thus

\bf 500+0.02x=2000\implies 0.02x=1500\implies x=\cfrac{1500}{0.02}\\\\\\ x=75000
4 0
3 years ago
Need step-by-step. Please answer correctly. This determines what grade I get. I will mark brainliest to the first person who ans
tatyana61 [14]

Answer:

  3√3

Step-by-step explanation:

For the problem shown here, your answer 3√3 is correct.

When there is a radical by itself in the denominator, you multiply numerator and denominator by a radical that results in the product being rational. For a square root, that will usually be the same square root:

  \dfrac{9}{\sqrt{3}}=\dfrac{9}{\sqrt{3}}\cdot\dfrac{\sqrt{3}}{\sqrt{3}}=\dfrac{9\sqrt{3}}{3}=\boxed{3\sqrt{3}}

__

If the problem has a sum in the denominator involving a square root, then you multiply numerator and denominator by the conjugate of that sum (the sum with the sign changed). This uses the special product "difference of squares" to eliminate the radical term.

<u>Example</u>:

  \dfrac{9}{2-\sqrt{3}}=\dfrac{9}{2-\sqrt{3}}\cdot\dfrac{2+\sqrt{3}}{2+\sqrt{3}}=\dfrac{9(2+\sqrt{3})}{2^2-(\sqrt{3})^2}=\dfrac{18+9\sqrt{3}}{4-3}\\\\=\boxed{18+9\sqrt{3}}

__

It is easy to demonstrate that none of the offered choices for this problem has the same value as 9/√3.

9/√3 ≈ 5.196. Offered choices have values of about 4.798, 1.732, 6.681, 23.196 -- none even close.

Please discuss this question with your teacher.

3 0
3 years ago
What is the area of the shaded sector of the circle?
oee [108]

Answer:

area if sector= teeta. ×πr²

360

<u>120</u>°. ×<u>2</u><u>2</u>×9×9

360. 7

<u>3×1782</u>

7

5346

5 0
3 years ago
For what values of x is rational expression below undefined x-7/x^2-7x-8
Novay_Z [31]
The values are x = 8 and x = -1.

To find the undefined values, we need to know when the denominator is zero.
To do this, we need to factor it and find the value that would make either factor equal to zero.

If factors to: (x - 8)(x + 1)

Therefore, the undefined values would be at 8 and -1.
8 0
3 years ago
Find the 9th term of an arithmetic sequence that has a 4th term of 27 and a 5th term of 19
Harman [31]

Answer:

-13

Step-by-step explanation:

5th term - 4th term = common difference

= 19 - 27

= -8

Thus the 9th term =   5th term +  4(-8)

=  19 - 32

= -13  (answer

4 0
3 years ago
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