(6-root 8)^2= a b root 2 where and are constants to be found.

Parallel lines x and w are cut by transversals z and y and form 4 angles at each intersection. Where line x intersects with line

Sunny_sXe [5.5K]

Answer:

m∠1°= 75°

m∠2°= 105°

Step-by-step explanation:

It's on edg.

5 0

3 years ago

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Jacey obtains a 30-year 6/2 ARM at 4% with a 2/6 cap structure in the amount of $224,500. What is the monthly payment during the

Juli2301 [7.4K]

General Idea:

We need to make use of the below formula to find the monthly payment..

$Monthly \; Payment\; =\; \frac{P \times \frac{r}{12}}{(1-(1+\frac{r}{12})^{-m})} \\ \\ Where:\\ P\; is\; Principal\\ r\; is\; rate\; in\; decimal\; form\\ m\; is\; number\; of\; monthly\; payments$

Applying the concept:

Given:

$P=\$224,500\\ r=4\%=0.04\\ m=30\; year \times 12 \; months/year=360\\$

Substituting the given in the formula we will get the monthly payment.

$Monthly\; Payment\; =\; \frac{224500 \times \frac{0.04}{12}}{(1-(1+\frac{0.04}{12})^{-360})} =\frac{\frac{8980}{12}}{(1-0.301796)} =\frac{748.3333}{0.698204} \\ \\ Monthly \; Payment= \$1071.7975$

Conclusion:

The monthly payment during the initial period is $1072.

3 0

4 years ago

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Which sets of values belong to the domain and range of a relation?

Gala2k [10]

Step-by-step explanation:

As we know that

The domain of a relation is defined as the set of all possible independent values the relation can really take - basically the group of all possible inputs.

The range of a relation is defined as the set of all possible dependent values the relation can generate from the domain values - basically the group of all possible outputs.

For example, considering the set of ordered pairs

$\left(-3,\:0\right),\:\left(0,\:6\right),\:\left(3,\:12\right),\:\left(6,\:18\right)$

As

The domain is the set of independent values, meaning the set of x-coordinates of the ordered pairs as x is an independent variable.

The range is set of dependent values, meaning the set of y-coordinates of the ordered pairs as y is an independent variable.

So, in the set of ordered pairs of a relation

$\left(-3,\:0\right),\:\left(0,\:6\right),\:\left(3,\:12\right),\:\left(6,\:18\right)$

$Domain:\:\left\{-3,\:0,\:3,\:6\right\}$

$Range:\:\left\{0,\:6,\:12,\:18\right\}$

Keywords: ordered pairs, domain, range, relation

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4 0

3 years ago

How old would i be in 1991 if i was born in 1987?

Elena L [17]

4 years old.

1991 -1987= 4

6 0

3 years ago

Please help.. ASAP Help Please do all

Semenov [28]

Answer:

1) 257

2) 24^1=24

3) 47/8(Decimal: 5.875) How to: 5/1+7/8 = 40/80+7/8 = 40 + 7 / 8 = 47/8

4)=920

5) =32.484

6) =33.444

7) = 4 : 1 How to: The GCF of 12 and 3 is 3 Divide both terms by the GCF, 3:

12 ÷ 3 = 4

3 ÷ 3 = 1 The ratio 12 : 3 can be reduced to lowest terms by dividing both terms by the GCF = 3 :

12 : 3 = 4 : 1

8) = 9 cups. How to: 2*3=6. so you multiply the other side (3) by 3 so 3*3=9 cups.

9) The second pack weighs more. How to: Since 45 ounces is 2.812 pounds (Formula

divide the mass value by 16) and 2.812 is less than 3 so second pack weighs more.

10) =26.6

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7 0

3 years ago